anonymous
  • anonymous
Solve this numerical syllogism for me: Eight of ten A's are B's; four of ten A's are C's. What is the minimum number of B's that are also C's?
Mathematics
schrodinger
  • schrodinger
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osanseviero
  • osanseviero
2 B´s are C´s
anonymous
  • anonymous
2 Bs would be the minimum number of Bs that can be Cs.

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