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The Orginial Perimeter was 33m and the Area was 27.

This is the last part of the question.

P would equal 11?

Our base was 12? I think

12 sounds right, youd have to dbl chk tho :)

Our base was 12? I think

Here let me draw it out real quick (:

Our base was 12? I think

|dw:1320881287444:dw|

base = 6 and height = 9 it looks like in that

Our base was 12? I think

P = 1/2 x 54

A =*

|dw:1320881588115:dw|

12/3 = 4
18/3 = 6

My bad lol

i just checked out your other post; it was 6 for the bottom and 9 for the height ....

the normal area, is then: 1/2 x 54 as you stated

if we divide all the sides by 3; that will go to:
1/(2*3*3) x 54
or simply
1/18 x 54

which is also:
1/2 * 6/3 * 9/3
1/2 * 2 * 3
1/2 x 6

A = 3

yep

Man thanks your real good at this math.

we can say that if the sides are divided by 3, then the area is divided by 3^2