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28Tylerr Group Title

Suppose the side lengths and height of the triangle were divided by three. What effect would this have on the perimeter? & The Area? Justify your answer @Geometry

  • 3 years ago
  • 3 years ago

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  1. 28Tylerr Group Title
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    The Orginial Perimeter was 33m and the Area was 27.

    • 3 years ago
  2. 28Tylerr Group Title
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    This is the last part of the question.

    • 3 years ago
  3. amistre64 Group Title
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    the perimeter is just like before; just divide it by 3; the area tho is nit a linear measurement and needs some work to it

    • 3 years ago
  4. 28Tylerr Group Title
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    P would equal 11?

    • 3 years ago
  5. 28Tylerr Group Title
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    Our base was 12? I think

    • 3 years ago
  6. amistre64 Group Title
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    12 sounds right, youd have to dbl chk tho :)

    • 3 years ago
  7. 28Tylerr Group Title
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    Our base was 12? I think

    • 3 years ago
  8. 28Tylerr Group Title
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    Here let me draw it out real quick (:

    • 3 years ago
  9. amistre64 Group Title
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    \[Area = \frac{1}{2}*base*height\] \[Area = \frac{1}{2}*\frac{base}{3}*\frac{height}{3}=\frac{1}{18}bh\]

    • 3 years ago
  10. 28Tylerr Group Title
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    Our base was 12? I think

    • 3 years ago
  11. 28Tylerr Group Title
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    |dw:1320881287444:dw|

    • 3 years ago
  12. amistre64 Group Title
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    base = 6 and height = 9 it looks like in that

    • 3 years ago
  13. 28Tylerr Group Title
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    Our base was 12? I think

    • 3 years ago
  14. 28Tylerr Group Title
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    P = 1/2 x 54

    • 3 years ago
  15. 28Tylerr Group Title
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    A =*

    • 3 years ago
  16. amistre64 Group Title
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    |dw:1320881588115:dw|

    • 3 years ago
  17. amistre64 Group Title
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    if you just divided the measures in half, then your not matching this problem. It wants the measures divided by 3

    • 3 years ago
  18. amistre64 Group Title
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    12/3 = 4 18/3 = 6

    • 3 years ago
  19. 28Tylerr Group Title
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    My bad lol

    • 3 years ago
  20. amistre64 Group Title
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    i just checked out your other post; it was 6 for the bottom and 9 for the height ....

    • 3 years ago
  21. amistre64 Group Title
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    the normal area, is then: 1/2 x 54 as you stated

    • 3 years ago
  22. amistre64 Group Title
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    if we divide all the sides by 3; that will go to: 1/(2*3*3) x 54 or simply 1/18 x 54

    • 3 years ago
  23. amistre64 Group Title
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    which is also: 1/2 * 6/3 * 9/3 1/2 * 2 * 3 1/2 x 6

    • 3 years ago
  24. 28Tylerr Group Title
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    A = 3

    • 3 years ago
  25. amistre64 Group Title
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    yep

    • 3 years ago
  26. 28Tylerr Group Title
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    Man thanks your real good at this math.

    • 3 years ago
  27. amistre64 Group Title
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    we can say that if the sides are divided by 3, then the area is divided by 3^2

    • 3 years ago
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