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anonymous
 5 years ago
Suppose the side lengths and height of the triangle were divided by three. What effect would this have on the perimeter? & The Area? Justify your answer @Geometry
anonymous
 5 years ago
Suppose the side lengths and height of the triangle were divided by three. What effect would this have on the perimeter? & The Area? Justify your answer @Geometry

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The Orginial Perimeter was 33m and the Area was 27.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is the last part of the question.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the perimeter is just like before; just divide it by 3; the area tho is nit a linear measurement and needs some work to it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Our base was 12? I think

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.112 sounds right, youd have to dbl chk tho :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Our base was 12? I think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here let me draw it out real quick (:

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[Area = \frac{1}{2}*base*height\] \[Area = \frac{1}{2}*\frac{base}{3}*\frac{height}{3}=\frac{1}{18}bh\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Our base was 12? I think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1320881287444:dw

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1base = 6 and height = 9 it looks like in that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Our base was 12? I think

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1dw:1320881588115:dw

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if you just divided the measures in half, then your not matching this problem. It wants the measures divided by 3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i just checked out your other post; it was 6 for the bottom and 9 for the height ....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the normal area, is then: 1/2 x 54 as you stated

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if we divide all the sides by 3; that will go to: 1/(2*3*3) x 54 or simply 1/18 x 54

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1which is also: 1/2 * 6/3 * 9/3 1/2 * 2 * 3 1/2 x 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Man thanks your real good at this math.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we can say that if the sides are divided by 3, then the area is divided by 3^2
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