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28Tylerr
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Suppose the side lengths and height of the triangle were divided by three. What effect would this have on the perimeter? & The Area? Justify your answer @Geometry
 3 years ago
 3 years ago
28Tylerr Group Title
Suppose the side lengths and height of the triangle were divided by three. What effect would this have on the perimeter? & The Area? Justify your answer @Geometry
 3 years ago
 3 years ago

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28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
The Orginial Perimeter was 33m and the Area was 27.
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
This is the last part of the question.
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the perimeter is just like before; just divide it by 3; the area tho is nit a linear measurement and needs some work to it
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
P would equal 11?
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
Our base was 12? I think
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
12 sounds right, youd have to dbl chk tho :)
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
Our base was 12? I think
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
Here let me draw it out real quick (:
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[Area = \frac{1}{2}*base*height\] \[Area = \frac{1}{2}*\frac{base}{3}*\frac{height}{3}=\frac{1}{18}bh\]
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
Our base was 12? I think
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
dw:1320881287444:dw
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
base = 6 and height = 9 it looks like in that
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
Our base was 12? I think
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
P = 1/2 x 54
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
dw:1320881588115:dw
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if you just divided the measures in half, then your not matching this problem. It wants the measures divided by 3
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
12/3 = 4 18/3 = 6
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
My bad lol
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i just checked out your other post; it was 6 for the bottom and 9 for the height ....
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the normal area, is then: 1/2 x 54 as you stated
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if we divide all the sides by 3; that will go to: 1/(2*3*3) x 54 or simply 1/18 x 54
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
which is also: 1/2 * 6/3 * 9/3 1/2 * 2 * 3 1/2 x 6
 3 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.1
Man thanks your real good at this math.
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
we can say that if the sides are divided by 3, then the area is divided by 3^2
 3 years ago
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