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Suppose the side lengths and height of the triangle were divided by three. What effect would this have on the perimeter? & The Area? Justify your answer @Geometry

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The Orginial Perimeter was 33m and the Area was 27.
This is the last part of the question.
the perimeter is just like before; just divide it by 3; the area tho is nit a linear measurement and needs some work to it

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Other answers:

P would equal 11?
Our base was 12? I think
12 sounds right, youd have to dbl chk tho :)
Our base was 12? I think
Here let me draw it out real quick (:
\[Area = \frac{1}{2}*base*height\] \[Area = \frac{1}{2}*\frac{base}{3}*\frac{height}{3}=\frac{1}{18}bh\]
Our base was 12? I think
base = 6 and height = 9 it looks like in that
Our base was 12? I think
P = 1/2 x 54
A =*
if you just divided the measures in half, then your not matching this problem. It wants the measures divided by 3
12/3 = 4 18/3 = 6
My bad lol
i just checked out your other post; it was 6 for the bottom and 9 for the height ....
the normal area, is then: 1/2 x 54 as you stated
if we divide all the sides by 3; that will go to: 1/(2*3*3) x 54 or simply 1/18 x 54
which is also: 1/2 * 6/3 * 9/3 1/2 * 2 * 3 1/2 x 6
A = 3
Man thanks your real good at this math.
we can say that if the sides are divided by 3, then the area is divided by 3^2

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