## anonymous 4 years ago Suppose the side lengths and height of the triangle were divided by three. What effect would this have on the perimeter? & The Area? Justify your answer @Geometry

1. anonymous

The Orginial Perimeter was 33m and the Area was 27.

2. anonymous

This is the last part of the question.

3. amistre64

the perimeter is just like before; just divide it by 3; the area tho is nit a linear measurement and needs some work to it

4. anonymous

P would equal 11?

5. anonymous

Our base was 12? I think

6. amistre64

12 sounds right, youd have to dbl chk tho :)

7. anonymous

Our base was 12? I think

8. anonymous

Here let me draw it out real quick (:

9. amistre64

$Area = \frac{1}{2}*base*height$ $Area = \frac{1}{2}*\frac{base}{3}*\frac{height}{3}=\frac{1}{18}bh$

10. anonymous

Our base was 12? I think

11. anonymous

|dw:1320881287444:dw|

12. amistre64

base = 6 and height = 9 it looks like in that

13. anonymous

Our base was 12? I think

14. anonymous

P = 1/2 x 54

15. anonymous

A =*

16. amistre64

|dw:1320881588115:dw|

17. amistre64

if you just divided the measures in half, then your not matching this problem. It wants the measures divided by 3

18. amistre64

12/3 = 4 18/3 = 6

19. anonymous

20. amistre64

i just checked out your other post; it was 6 for the bottom and 9 for the height ....

21. amistre64

the normal area, is then: 1/2 x 54 as you stated

22. amistre64

if we divide all the sides by 3; that will go to: 1/(2*3*3) x 54 or simply 1/18 x 54

23. amistre64

which is also: 1/2 * 6/3 * 9/3 1/2 * 2 * 3 1/2 x 6

24. anonymous

A = 3

25. amistre64

yep

26. anonymous

Man thanks your real good at this math.

27. amistre64

we can say that if the sides are divided by 3, then the area is divided by 3^2