A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

Thephillup
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1320896121958:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1is the problem unclear or is the problem exactly as stated?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{8}x+1=5 => \sqrt{8}x=51=> \sqrt{8}x=4 => (\sqrt{8}x)^2=4^2\] \[=>8x^2=16 => x^2=2 => x = \pm \sqrt{2}\] But only \[x=\sqrt{2} \text{ is a solution} \]

Ducky44
 3 years ago
Best ResponseYou've already chosen the best response.0√x  7 + 5 = 11 show work

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[\text{for some reason I think you meant } \sqrt{8x+1}=5\] square both sides \[8x+1=5^2\] 8x+1=25 subtract 1 on both sides 8x=251 8x=24 divide by 8 on both sides x=3 check your result: \[\sqrt{8(3)+1}=\sqrt{25}=5\] both sides are the same x=3 is a solution!

Thephillup
 3 years ago
Best ResponseYou've already chosen the best response.0Wouldn't x=2 because 2*8=16 sqt16=4 4+1=5
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.