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x = 8 y = 5
see as it is divisible by 275 means y will be either 5 or, 0
and 275 = 5*5*11
that is the resultant should be divisible by 11
thus the 33xy2y should be divisible by 11. That is the difference of sum of digits at odd place with the sum of digits at even places should be either 0 or, 11, or, multiple of 11
sum of odd place digits is 5+x and sum of even place digit is 3 +2y
Difference is (5+x) - (3+2y) it should be either 0 / 11/ multiple of 11
difference is 2 + x - 2y
y can be either 0 or, 5
when y = 0 therefore we have 2 + x (it should be 0 / 11 / multiple of 11) but in no case it is possible so Y cannot be 0
so when y = 5 then we have 2 + x - 2*5 = 2 + x -10 = -8 + x
yes but then it is not divisible by 275
if x = 9 in that case it is not divisible by 275
so it cannot be 9
now we got -8 + x for what value of x u will have either 0 / 11 / multiple of 11
ok thnx u always make me understand thnx a lot...............!!!!!!!!
so got the point how many rules u have to apply.........
another thing that u can do is use short cut that is calculator......hahaha satisfied with the answer
yup 100% satisfied
hey actually u tried to understand the thing other pplare just interested in answers not in the procedure so i gave u a medal