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factorize it

how watever i get is not a prime number

why?

oh

but then ii have to plug in millions of values

what u want to calculate

(n^3 -8n^2+20n-13) a prime number

or n is a prime number

ok

so,what to do??

anything i can do to narrow down the possobilities

no answer given....

ok see for 2 it is prime number

wait i took wrong concept

\[(x-1) \times [(x-7)x + 13]\]

where x is n

ok

now see the first term is (x-1).
and other than 2 no other even number is a prime number right

i got the answer

no n does not have to be a prime number n^3 -8n^2+20n-13 has to be a prime number

yeah i know
(x−1)×[(x−7)x+13]
it has to be prime

yup so x can be anything greater or equal to 2

first term is (x-1) and two is the only even prime number.

but if u will subtract 1 from any other prime number the resultant will be divisible by 2

getting my point or not

x can be 4

yeah u r right

it means that for any odd integer other than 3 u will not get a prime number

yeah

Superb sheggy!

also the number cannot be graeter than 7

oh yeah

thanks fool bhai

so u are having a limited space to work out that is from 1 to 7

yes sheg u got it so answer is n=2,3,4

no actually 2 to 7

hahahaa right 2 to 7

but for 7 it will be 0

wait why cant it be greater than 7?

try any number u will get the answer

odd numbers cannot be included ok thats true

is 323 a prime number?

yeah i acept

its not div by 17

323 is divisible by 17

so 323 is not a prime number

4387
?

what u have put x = ??

n=20

1443?

gtg shall come bak in 15 min

for n = 20 it should be equal to 5187

oh yeah 1443?

no

20^3 - 8*20^2 + 20*20 -13
=8000 - 3200 + 400 -13
= 8400 - 3213
= 5187

gtg cum bak in 15 mins

dear i had told u for no value greater than 7 it would fit

and both 1443 and 5187 is divisible by 3

i am bak
so what to do now?

for no value greater than 7 that too even number it will not be a prime number

king u there