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A man 6 feet tall walks at a rate of 13 feet per second away from a light that is 15 feet above the ground. When he is 8 feet from the base of the light, at what rate is the tip of his shadow moving?

Calculus1
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HINT HINT: Use similar Triangles!
yup..gigles is right
another hint. the rate of change will be a constant, the "when he is 8 feet" will have nothing to do with it.

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Other answers:

|dw:1320959290284:dw| use \[\frac{x}{6}=\frac{x+y}{15}\] to get a relation between x and y. you know \[y'=13\] and you want \[x'\]

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