A man 6 feet tall walks at a rate of 13 feet per second away from a light that is 15 feet above the ground. When he is 8 feet from the base of the light, at what rate is the tip of his shadow moving?

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A man 6 feet tall walks at a rate of 13 feet per second away from a light that is 15 feet above the ground. When he is 8 feet from the base of the light, at what rate is the tip of his shadow moving?

Calculus1
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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HINT HINT: Use similar Triangles!
yup..gigles is right
another hint. the rate of change will be a constant, the "when he is 8 feet" will have nothing to do with it.

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Other answers:

|dw:1320959290284:dw| use \[\frac{x}{6}=\frac{x+y}{15}\] to get a relation between x and y. you know \[y'=13\] and you want \[x'\]

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