sdresser
multiply or divide as indicated and reduce to lowest terms where appropriate: 2x-4/5x X 15x/x-2
multiply or divide as indicated and reduce to lowest terms where appropriate: 2x-4/5x X 15x/x-2
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sdresser
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how the hell?!
Jemurray3
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I assume that is
\[\frac{2x-4}{5x}\frac{15x}{x-2} \]
right?
Jemurray3
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You can rewrite that like this...
\[\frac{2(x-2)}{5x}\frac{3(5x)}{x-2} \]
which would be six, no?
sdresser
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correct how did u write it like that? i cant write it like that in the question box
sdresser
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but i dont know how you are even re writing it
Jemurray3
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It's called LaTeX, don't worry about it. And just look at it, I dunno what else to tell you really. 2x-4 = 2(x-2), right?
sdresser
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yes
Jemurray3
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So, the (x-2)'s cancel, and the 5x's cancel, leaving you with 2*3 = 6.
sdresser
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ohhhhh okay thank you!
sdresser
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so what about -8 X n/-3msquared
Jemurray3
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you can cancel the negative signs.
sdresser
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this is such hard math
sdresser
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i dont know how to calculate algebraic functions
Jemurray3
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Such as?
sdresser
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i dont know to write it
sdresser
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(5/pqSQUARED) ( -3pCUBEDr/10q)
Jemurray3
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\[\frac{5}{pq^2}\frac{-3p^3r}{10q}\]
?
sdresser
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how do u do that?
Jemurray3
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You'll notice the "Equation" button just below the text box.
sdresser
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i see it but i havent figured out how to work it
Jemurray3
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It's a document typesetting language called LaTeX. If you can't work the buttons don't worry about it because what I just typed looks like this:
"\frac{5}{pq^2} \frac{-3p^3r}{10q} "
Jemurray3
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I understood what you meant well enough when you just typed it.
sdresser
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okie doke
Jemurray3
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And to answer your question, that would be
\[\frac{-15p^3r}{10pq^3} = \frac{-3p^2r}{2q^3}\]
sdresser
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can you explain how you got that?
Jemurray3
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I can tell you that when you multiply fractions, you multiply the numerators and denominators together, and that 15 and 10 share a common factor of 5 so that reduces to 3/2 when you cancel it, and p^3 / p = p^2, but besides that, I apologize, I do not know how to explain it further.
sdresser
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thanks i just not that good at math