A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
There is a 0.63 probability that Mobil stock will rise, a 0.75 probability Gulf stock will rise and a 0.4 chance that both stocks will rise. Find the probability that neither stock will rise. There is a 0.63 probability that Mobil stock will rise, a 0.75 probability Gulf stock will rise and a 0.4 chance that both stocks will rise. Find the probability that neither stock will rise. @Mathematics
anonymous
 5 years ago
There is a 0.63 probability that Mobil stock will rise, a 0.75 probability Gulf stock will rise and a 0.4 chance that both stocks will rise. Find the probability that neither stock will rise. There is a 0.63 probability that Mobil stock will rise, a 0.75 probability Gulf stock will rise and a 0.4 chance that both stocks will rise. Find the probability that neither stock will rise. @Mathematics

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So .37*.25=.0925 But the answer key for a similar problem( only difference is .47 instead of .4), the answer is .2775. The answers shouldnt differ that much right?

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2why are you multiplying those two numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0isnt that how you get the probability for AND?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then Im completely lost.

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2your events are NOT independent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think that's the concept that I dont quite understand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would the formula be P(A U B)/P(A)?

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2use \[P(A^c\cap B^c)=1P(A\cup B)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the 1P(none) formula

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2for any event E \[P(E)=1P(E^c)\] or \[P(E^c)=1P(E)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how exactly does not being independent effect the problem?

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2events A and B are independent iff \[P(A\cap B)=P(A)P(B)\]

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2you cant use this formula since A and B are not independent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So in terms of a venn diagram, independent is two circles that dont intersect. and not independent has two circles that do intersect. and in this problem the intersection is .4? So I need to find the sum of each part of the venn diagram, subtract from one (to get the number outside the diagram) which would be the "neither". Correct?

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2independent events intersect (most of the time)

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2if A and B are independent and P(A)>0 and P(B)>0 then A and B have to intersect.

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2use \[P(A^c\cap B^c)=1P(A\cup B)=1[P(A)+P(B)P(A\cap B)]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1321204843404:dw Is what Im picturing Basically, I was doing P(Ac∩Bc)=1−P(A∪B)=1−[P(A)+P(B)−P(A∩B)] except that mine adds instead of subtracts the intersection.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so to get neither dont you need to get rid of all that is in the circles? including the intersection?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldnt that be adding the intersection? so 1−[P(A)+P(B)+P(A∩B)] instead of 1−[P(A)+P(B)−P(A∩B)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1321205205257:dw So the answer is .02? that's seems really small.(compared to the other answer)

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2I would check your key again...if you just change from .4 to .47 then .2775 is not the answer
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.