A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Two ships leave a port at 9 A.M. One travels
at a bearing of N 53
◦ W at 12 miles per hour
and the other travels at a bearing of S 67
◦ W
at 16 miles per hour.
Approximate how far apart they are at
noon that day.
Answer in units of mi
anonymous
 4 years ago
Two ships leave a port at 9 A.M. One travels at a bearing of N 53 ◦ W at 12 miles per hour and the other travels at a bearing of S 67 ◦ W at 16 miles per hour. Approximate how far apart they are at noon that day. Answer in units of mi

This Question is Closed

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1After you draw your picture, you see that you are talking about a triangle with a 60 degree angle. The sides that form the 60 degree angle are 3(12) and 3(16) or 36 and 48. So now you can use the law of cosines using the 60 degree angle as C and the required distance as c. So: c^2 = 48^2+36^2  2(48)(36)cos 60 c^2 = 2304+12963456(.5) c^2 = 36001728 c^2 = 1872 c = 43.3 miles
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.