anonymous
  • anonymous
Two ships leave a port at 9 A.M. One travels at a bearing of N 53 ◦ W at 12 miles per hour and the other travels at a bearing of S 67 ◦ W at 16 miles per hour. Approximate how far apart they are at noon that day. Answer in units of mi
Mathematics
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anonymous
  • anonymous
Two ships leave a port at 9 A.M. One travels at a bearing of N 53 ◦ W at 12 miles per hour and the other travels at a bearing of S 67 ◦ W at 16 miles per hour. Approximate how far apart they are at noon that day. Answer in units of mi
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Mertsj
  • Mertsj
After you draw your picture, you see that you are talking about a triangle with a 60 degree angle. The sides that form the 60 degree angle are 3(12) and 3(16) or 36 and 48. So now you can use the law of cosines using the 60 degree angle as C and the required distance as c. So: c^2 = 48^2+36^2 - 2(48)(36)cos 60 c^2 = 2304+1296-3456(.5) c^2 = 3600-1728 c^2 = 1872 c = 43.3 miles

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