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Identify the Horizontal Asymptotes of
g(x) = (3x+2)/((x^2)+4)^(1/2))
 2 years ago
 2 years ago
Identify the Horizontal Asymptotes of g(x) = (3x+2)/((x^2)+4)^(1/2))
 2 years ago
 2 years ago

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AnachronismBest ResponseYou've already chosen the best response.0
dw:1321422281732:dw
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
The answer is at 3 and 3
 2 years ago

AnachronismBest ResponseYou've already chosen the best response.0
how would I go about finding those answers? :/ my teacher hasn't taught us how to find it with radicals in the denominator, so I'm lost.
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
well you look at the ratio of the exponents. The numerator is 3x and the denomintor will just be x. it is x^(2*1/2) = x so the ratio is just 3x/x. As x goes to infinity you get a horizontal asymptote of 3 As x goes to negative infinity you get a horizontal asymptote of 3
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
understand? I know it probably sounds very confusing
 2 years ago

AnachronismBest ResponseYou've already chosen the best response.0
I kind of get it, but would it just be 3, then because if I substitute a large negative number for x it is a negative over a negative, and I would still get a positive 3
 2 years ago

AsankaBest ResponseYou've already chosen the best response.0
if you know how to differentiate it , then differentiate it w.r.t x and equate the answer to 0
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
i dont think she is at that type of math yet, that will be too complex at this point
 2 years ago

AsankaBest ResponseYou've already chosen the best response.0
sorry guys i am new to this so i do not know your standards
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
No the answer will be 3 as you approach infinity because you need to take into account the ratio 3/1
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
the top will outdo the bottom in this case, a very large negative number times 3 will approach 3 faster then the denomnator will reduce it to 3. Understand? it is confusing but take a second to think about it
 2 years ago

AnachronismBest ResponseYou've already chosen the best response.0
It's alright, thank you for trying to explain it to me Asanka. I think I just visualized it, and it seems to make sense if the numerator is going three times as fast. Thanks a lot for all your help :)
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
exactly you got it! anytime
 2 years ago

tsegu_kBest ResponseYou've already chosen the best response.2
I am attaching the solution hoping it will help
 2 years ago

tdabboudBest ResponseYou've already chosen the best response.0
Nice work! very neat.. but you can just look at the ratio of like exponents to make it a little easier, but either way nice job
 2 years ago
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