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ta123
 4 years ago
need help on the attachment @Calculus1
ta123
 4 years ago
need help on the attachment @Calculus1

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across
 4 years ago
Best ResponseYou've already chosen the best response.1\[f'(x)=4x\implies f(1)=4,\]\[f(1)=2.\]

across
 4 years ago
Best ResponseYou've already chosen the best response.1\[f_{1}^{1}(x)=\sqrt{\frac{1}{2}x}\]\[f_{2}^{1}(x)=\frac{x+2}{4}\]

across
 4 years ago
Best ResponseYou've already chosen the best response.1\[\int_{0}^{2}\int_{\sqrt{\frac{y}{2}}}^{\frac{y+2}{4}}dxdy\]

across
 4 years ago
Best ResponseYou've already chosen the best response.1There it is. Can you evaluate that integral?

ta123
 4 years ago
Best ResponseYou've already chosen the best response.1I believe so, you just have to separate both them right?

across
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{4}\int_{0}^{2}ydy+\frac{1}{2}\int_{0}^{2}dy\sqrt{\frac{1}{2}}\int_{0}^{2}\sqrt{y}dy\]yep

across
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{8}\left[y^2\right]_{0}^{2}+\frac{1}{2}\left[y\right]_{0}^{2}\frac{1}{3}\sqrt{2}\left[y^{\frac{3}{2}}\right]_{0}^{2}\]seems a bit tedious though, but it gives the right answer :/

across
 4 years ago
Best ResponseYou've already chosen the best response.1There has got to be an easier method.

ta123
 4 years ago
Best ResponseYou've already chosen the best response.1thanks again across, like the new pic of you

across
 4 years ago
Best ResponseYou've already chosen the best response.1Thought it'd look more "professional." n_O Thank you.
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