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ta123
need help on the attachment @Calculus1
\[\int_{0}^{1}\pi(\sqrt[4]{x})^2dx-\int_{0}^{1}\pi(x^4)^2dx\]
how come but side are the same
oh, wait my eyes are playing tricks on me I thought I saw a square root in the right integral
Yeah, integrals will do that to your eyes. :P
I got 7pi/9 is that what you got?
\[\pi\int_{0}^{1}\sqrt{x}dx=\frac{2}{3}\pi\left[x^{\frac{3}{2}}\right]_{0}^{1}=\frac{2}{3}\pi,\]\[\pi\int_{0}^{1}x^8dx=\pi\left[\frac{1}{9}x^9\right]_{0}^{1}=\frac{1}{5}=\frac{1}{9}\pi,\]\[\frac{2}{3}\pi-\frac{1}{9}\pi=\frac{5}{9}\pi.\]
dang I integrated wrong by different number number to the exponents beside the number 1
oops! I forgot "adding" in between by and different