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across Group TitleBest ResponseYou've already chosen the best response.1
\[\int_{0}^{1}\pi(\sqrt[4]{x})^2dx\int_{0}^{1}\pi(x^4)^2dx\]
 3 years ago

ta123 Group TitleBest ResponseYou've already chosen the best response.1
how come but side are the same
 3 years ago

across Group TitleBest ResponseYou've already chosen the best response.1
What do you mean?
 3 years ago

ta123 Group TitleBest ResponseYou've already chosen the best response.1
oh, wait my eyes are playing tricks on me I thought I saw a square root in the right integral
 3 years ago

across Group TitleBest ResponseYou've already chosen the best response.1
Yeah, integrals will do that to your eyes. :P
 3 years ago

ta123 Group TitleBest ResponseYou've already chosen the best response.1
I got 7pi/9 is that what you got?
 3 years ago

across Group TitleBest ResponseYou've already chosen the best response.1
They're subtracting.
 3 years ago

across Group TitleBest ResponseYou've already chosen the best response.1
\[\pi\int_{0}^{1}\sqrt{x}dx=\frac{2}{3}\pi\left[x^{\frac{3}{2}}\right]_{0}^{1}=\frac{2}{3}\pi,\]\[\pi\int_{0}^{1}x^8dx=\pi\left[\frac{1}{9}x^9\right]_{0}^{1}=\frac{1}{5}=\frac{1}{9}\pi,\]\[\frac{2}{3}\pi\frac{1}{9}\pi=\frac{5}{9}\pi.\]
 3 years ago

ta123 Group TitleBest ResponseYou've already chosen the best response.1
dang I integrated wrong by different number number to the exponents beside the number 1
 3 years ago

ta123 Group TitleBest ResponseYou've already chosen the best response.1
oops! I forgot "adding" in between by and different
 3 years ago
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