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cutegirl

  • 4 years ago

Starting from 1.5 miles away, a car drives towards a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d=l1.5-53tl . At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. 95.1s and 108.7s 10.2s and 101.9s 108.7s and 10.2s 95.1s and 10.2s

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  1. asnaseer
    • 4 years ago
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    \[d=|1.5-53t|\]where d is in miles and t is in hours. first divide both sides by 53 to get:\[\frac{d}{53}=|\frac{1.5}{53}-t|\]this can be split into two portions: (1) for t <= 1.5/53 hours we can write:\[\frac{d}{53}=\frac{1.5}{53}-t\]\[t=\frac{1.5-d}{53}\] (2) for t > 1.5/53 hours we can write:\[\frac{d}{53}=-(\frac{1.5}{53}-t)=t-\frac{1.5}{53}\]\[t=\frac{1.5+d}{53}\] now just stick the value d=0.1 into (1) and (2) above to get your answer (remember to multiply the answers you get by 3600 to convert hours to seconds).

  2. cutegirl
    • 4 years ago
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    thank you so much

  3. asnaseer
    • 4 years ago
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    yw

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