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patbatE21

  • 4 years ago

Find d/dx tanh^-1 (1-x^2) .....this I have no clue about, a walk through would be nice

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  1. patbatE21
    • 4 years ago
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    I know its an inverse hyperbolic function

  2. FoolForMath
    • 4 years ago
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    $$ y = arctanh (1-x^2) \Rightarrow \tanh y = (1-x^2)$$ can you do the rest ?

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