At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

\[1^3 + 2^3 + 3^3 +.....+ 10^3 = \sum_{1}^{10}N^3\]

$$ \sum \limits_{i=1}^{10} i^3 $$

I never Understood sigma notation
Someone please Explain Me =)

sigma means summation

see what i have written above i.e., answer

in above expression it is sum of cubes of first 10 natural numbers

fool is right ^^^^^^

What is there on top ,bottom and left ?

Could you explain why you write 10 up there ?

10 is the number of terms or number of iterations

\[\sum_{N=1}^{10}N^3 = 1^3 +2^3 + 3^3 + 4^3 +5^3 + 6^3 + 7^3 + 8^3 +9^3 + 10^3\]

\[\sum_{n= 1}^{50}(2n-1) = 1+3+5+7+....+99\]

this is arithmetic progression, how you find the number of terms in an A.P ? ;)

Understood =)

is that ok fool bro

using the formula Sn = n/2(a+l), right ?

I would never dare to doubt sheggy ;)

hahahaha buddy i just asked u

But Sheg why is that 50 at the top?

Yes barboat .. plug in the values of a and b and find n

same to you aditi

\[\sum_{1}^{99}\] is'nt it like this

Sorry n =1 at the bottom

No, it's an arithmetic progression .. find the n-th term

a = 1 last term = 99 , d = 2 what is n ?

aditi the total number of first 50 odd natural numbers are there so i had put 50 at the top

how come first 50 ?

aditi you know about arithmetic progression ?

Yup

then use it :) and sheggy point of view is also the same .. 1,3,5,7 so what is the 50th odd number ?

i thought the top one was last term and bottom first term

No it is the number of iteration

so, Sn= n/2 (100) ? but what do i write on the Sn side ? i cant solve it otherwise

iteration?

WOW I dont Know Maths =D

number of times you want to execute the operation.

itration amt batao usko

No you know maths .. don't give up so easy :)

bataoo

which one is number of times you want to execute the operation.

hahaha,.............see in simple words it is number of odd numbers that u have to add

aditi in which class u r

Sheg grade 1 =P

number of times you want to execute the operation is upper limit - lower limit..

or Grade 1+1 =P

ok gr8 so u have to work hard

I learnt AP without Sigma

you could write sigma notation in various ways

so, Sn= n/2 (100) ? but what do i write on the Sn side ? i cant solve it otherwise

just purchase this book K.C.Sinha

AP is not sigma .. you will learn sigma probably while doing Riemann sums in definite integral

Ok i understood something =P Thanks Fool and Sheg =D
Take My Medals =) here you go

thanks but I think you did not understand it ? :/

i understood the question barboat asked =)

fool buy books by Dr. K. C. Sinha it will help u alot....the books written by him are simply awesome

books are so heavy , i would rather carry a Laptop =P

btw $$1+3+5+7+99 = \sum \limits_{i =-5}^{45} (2n+11)$$ am I right ?

here nth term = 99,
a= 1
d = 2
n = ?
now plug in these values u will get n

I have read the classics Hall and knight in higher algebra sheggy ;)

isnt the formula Sn=n/2 (2a+(n-1)d) ?

btw indians can also write some classics

sorry buddy I hurt to say but I don't agree . most indian authors plagiarized these classics :(

barboat b4 applying that formula u have to apply nth term formula for finding out number of terms

Do you know abut the famous Kanetkar books for C and datastructure ?

I don't know about finance but I haven't found any in my domain ..

Aha that's an interesting fact :)

yeah just google out Aswath Damodaran he is real gem.......m dying to meet this finance wizard

Hmm