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Tomas.A
 3 years ago
Best ResponseYou've already chosen the best response.3\[(x+2)(x+1)=5\] \[x^2+x+2x+25=0\] \[x^2+3x3=0\] \[D=3\cdot34\cdot(3)\cdot1=21\] \[x_{1,2}=\frac{3\pm\sqrt{21}}{2}\]

alfie
 3 years ago
Best ResponseYou've already chosen the best response.1Anyhow, this is how you do a product... (a+b)(c+d) = a*c+b*d+a*d+b*c.

davidmckenna
 3 years ago
Best ResponseYou've already chosen the best response.0x * x = x^2 x * 1 = 1x 2 * x = 2x 2 * 1 = 2 Then add them all up and simplify where necessary: x^2x7 = 0 Then: x^2x = 7 And from here I'm stuck aslo :L

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1thomas i think there was suppose to be a minus between x and 2 \[(x2)(x+1)=5\] \[x^22x+x2=5\] \[x^2x25=0\] \[x^2x7=0\] \[x=\frac{1 \pm \sqrt{14(1)(7)}}{2}\]

Tomas.A
 3 years ago
Best ResponseYou've already chosen the best response.3@myininaya oh yeah sorry, i missed it ><
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