## davidmckenna 3 years ago Simplify x^2 - 9 / 2x^2 - 3x -9

1. davidmckenna

Sorry I'm trying to write this out in proper equation

2. saifoo.khan

$\frac{ x^2 - 9}{2x^2 - 3x -9}$

3. saifoo.khan

Like that right?

4. davidmckenna

Yes that's it

5. davidmckenna

Couldn't dot he divide thing

6. saifoo.khan

$\frac{(x-3)(x+3)}{(x-3) (2 x+3)}$ $\frac{\cancel{(x-3)}(x+3)}{\cancel{(x-3)} (2 x+3)}$

7. saifoo.khan

$\frac{x+3}{2x+3}$

8. davidmckenna

Could you explain like step by step, sorry I'm not very good at this

9. saifoo.khan

What u have to do is, u have to factor the both numerator and denominator..

10. saifoo.khan

After factoring, u will get, $\frac{(x-3)(x+3)}{(x-3) (2 x+3)}$ Now u have to cancel the like terms, leaving u with, $\frac{x+3}{2x+3}$

11. davidmckenna

Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!

12. saifoo.khan

No problem! ^_^