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davidmckenna

Simplify x^2 - 9 / 2x^2 - 3x -9

  • 2 years ago
  • 2 years ago

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  1. davidmckenna
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    Sorry I'm trying to write this out in proper equation

    • 2 years ago
  2. saifoo.khan
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    \[\frac{ x^2 - 9}{2x^2 - 3x -9}\]

    • 2 years ago
  3. saifoo.khan
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    Like that right?

    • 2 years ago
  4. davidmckenna
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    Yes that's it

    • 2 years ago
  5. davidmckenna
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    Couldn't dot he divide thing

    • 2 years ago
  6. saifoo.khan
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    \[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\] \[\frac{\cancel{(x-3)}(x+3)}{\cancel{(x-3)} (2 x+3)}\]

    • 2 years ago
  7. saifoo.khan
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    \[\frac{x+3}{2x+3}\]

    • 2 years ago
  8. davidmckenna
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    Could you explain like step by step, sorry I'm not very good at this

    • 2 years ago
  9. saifoo.khan
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    What u have to do is, u have to factor the both numerator and denominator..

    • 2 years ago
  10. saifoo.khan
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    After factoring, u will get, \[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\] Now u have to cancel the like terms, leaving u with, \[\frac{x+3}{2x+3}\]

    • 2 years ago
  11. davidmckenna
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    Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!

    • 2 years ago
  12. saifoo.khan
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    No problem! ^_^

    • 2 years ago
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