anonymous
  • anonymous
Simplify x^2 - 9 / 2x^2 - 3x -9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Sorry I'm trying to write this out in proper equation
saifoo.khan
  • saifoo.khan
\[\frac{ x^2 - 9}{2x^2 - 3x -9}\]
saifoo.khan
  • saifoo.khan
Like that right?

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anonymous
  • anonymous
Yes that's it
anonymous
  • anonymous
Couldn't dot he divide thing
saifoo.khan
  • saifoo.khan
\[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\] \[\frac{\cancel{(x-3)}(x+3)}{\cancel{(x-3)} (2 x+3)}\]
saifoo.khan
  • saifoo.khan
\[\frac{x+3}{2x+3}\]
anonymous
  • anonymous
Could you explain like step by step, sorry I'm not very good at this
saifoo.khan
  • saifoo.khan
What u have to do is, u have to factor the both numerator and denominator..
saifoo.khan
  • saifoo.khan
After factoring, u will get, \[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\] Now u have to cancel the like terms, leaving u with, \[\frac{x+3}{2x+3}\]
anonymous
  • anonymous
Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!
saifoo.khan
  • saifoo.khan
No problem! ^_^

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