davidmckenna
Simplify x^2  9 / 2x^2  3x 9



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davidmckenna
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Sorry I'm trying to write this out in proper equation

saifoo.khan
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\[\frac{ x^2  9}{2x^2  3x 9}\]

saifoo.khan
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Like that right?

davidmckenna
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Yes that's it

davidmckenna
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Couldn't dot he divide thing

saifoo.khan
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\[\frac{(x3)(x+3)}{(x3) (2 x+3)}\]
\[\frac{\cancel{(x3)}(x+3)}{\cancel{(x3)} (2 x+3)}\]

saifoo.khan
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\[\frac{x+3}{2x+3}\]

davidmckenna
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Could you explain like step by step, sorry I'm not very good at this

saifoo.khan
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What u have to do is, u have to factor the both numerator and denominator..

saifoo.khan
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After factoring, u will get,
\[\frac{(x3)(x+3)}{(x3) (2 x+3)}\]
Now u have to cancel the like terms, leaving u with,
\[\frac{x+3}{2x+3}\]

davidmckenna
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Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!

saifoo.khan
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No problem! ^_^