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davidmckenna Group TitleBest ResponseYou've already chosen the best response.0
Sorry I'm trying to write this out in proper equation
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.4
\[\frac{ x^2  9}{2x^2  3x 9}\]
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.4
Like that right?
 3 years ago

davidmckenna Group TitleBest ResponseYou've already chosen the best response.0
Yes that's it
 3 years ago

davidmckenna Group TitleBest ResponseYou've already chosen the best response.0
Couldn't dot he divide thing
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.4
\[\frac{(x3)(x+3)}{(x3) (2 x+3)}\] \[\frac{\cancel{(x3)}(x+3)}{\cancel{(x3)} (2 x+3)}\]
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.4
\[\frac{x+3}{2x+3}\]
 3 years ago

davidmckenna Group TitleBest ResponseYou've already chosen the best response.0
Could you explain like step by step, sorry I'm not very good at this
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.4
What u have to do is, u have to factor the both numerator and denominator..
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.4
After factoring, u will get, \[\frac{(x3)(x+3)}{(x3) (2 x+3)}\] Now u have to cancel the like terms, leaving u with, \[\frac{x+3}{2x+3}\]
 3 years ago

davidmckenna Group TitleBest ResponseYou've already chosen the best response.0
Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.4
No problem! ^_^
 3 years ago
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