Simplify x^2 - 9 / 2x^2 - 3x -9

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Simplify x^2 - 9 / 2x^2 - 3x -9

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Sorry I'm trying to write this out in proper equation
\[\frac{ x^2 - 9}{2x^2 - 3x -9}\]
Like that right?

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Yes that's it
Couldn't dot he divide thing
\[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\] \[\frac{\cancel{(x-3)}(x+3)}{\cancel{(x-3)} (2 x+3)}\]
\[\frac{x+3}{2x+3}\]
Could you explain like step by step, sorry I'm not very good at this
What u have to do is, u have to factor the both numerator and denominator..
After factoring, u will get, \[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\] Now u have to cancel the like terms, leaving u with, \[\frac{x+3}{2x+3}\]
Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!
No problem! ^_^

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