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davidmckenna
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry I'm trying to write this out in proper equation

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.4\[\frac{ x^2  9}{2x^2  3x 9}\]

davidmckenna
 3 years ago
Best ResponseYou've already chosen the best response.0Couldn't dot he divide thing

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.4\[\frac{(x3)(x+3)}{(x3) (2 x+3)}\] \[\frac{\cancel{(x3)}(x+3)}{\cancel{(x3)} (2 x+3)}\]

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.4\[\frac{x+3}{2x+3}\]

davidmckenna
 3 years ago
Best ResponseYou've already chosen the best response.0Could you explain like step by step, sorry I'm not very good at this

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.4What u have to do is, u have to factor the both numerator and denominator..

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.4After factoring, u will get, \[\frac{(x3)(x+3)}{(x3) (2 x+3)}\] Now u have to cancel the like terms, leaving u with, \[\frac{x+3}{2x+3}\]

davidmckenna
 3 years ago
Best ResponseYou've already chosen the best response.0Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!
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