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I tryed doing this question but i keep doing it wrong.
Solve 2  3x = 7.
A. {5/3, 3}
B. {15, 3}
C. {3, 5/3}
D. {3, 15}
 2 years ago
 2 years ago
I tryed doing this question but i keep doing it wrong. Solve 2  3x = 7. A. {5/3, 3} B. {15, 3} C. {3, 5/3} D. {3, 15}
 2 years ago
 2 years ago

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lilg132Best ResponseYou've already chosen the best response.0
it would help if you clicked good answer after people have answered it
 2 years ago

neverforgetvivisteeBest ResponseYou've already chosen the best response.1
before you do anything, you have to get the numbers in the absolute value sign alone. In this equation, you do. So now you can just solve like a regular algebra problem. First problem will have what's NOT in the absolute value sign negative and positive. so first, you can do a problem where 7 is positive, and another problem where 7 is negative so 23x = 7 solve like a regular algebra problem 3x=9 x=3 now make 7 positive 23x=7 solve regularly 3x=5 x= 5/3
 2 years ago

neverforgetvivisteeBest ResponseYou've already chosen the best response.1
but it loooks like it's not on your list but im pretty sure it's right http://www.wolframalpha.com/input/?i=%7C2++3x%7C+%3D+7
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
\[3x2=7\] \[3x2=7\text{ or } 3x2=7\] \[x=3 \text { or } x=\frac{5}{3}\]
 2 years ago
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