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anonymous
 4 years ago
(4/x1) + (5)/[(x+1)(x1)] **** Would i be able to cross out the (x1) in the denomerator?******
anonymous
 4 years ago
(4/x1) + (5)/[(x+1)(x1)] **** Would i be able to cross out the (x1) in the denomerator?******

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fretje
 4 years ago
Best ResponseYou've already chosen the best response.0(x+1)(x1) equals x²1 so you get (4/x1) + (5)/(x²1)

fretje
 4 years ago
Best ResponseYou've already chosen the best response.0that looks cleaner, but it is not simpler
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