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anonymous
 5 years ago
The graph of y = x2 is shown below. Using complete sentences, explain how the graph
of y = –2(x + 3)2 + 1 would differ from this parabola?
anonymous
 5 years ago
The graph of y = x2 is shown below. Using complete sentences, explain how the graph of y = –2(x + 3)2 + 1 would differ from this parabola?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry..not a good artist..the vertex is (0,0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1322072661463:dw

karatechopper
 5 years ago
Best ResponseYou've already chosen the best response.3r u doing absolute valuee functions/equations?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes..I need hlep with this

karatechopper
 5 years ago
Best ResponseYou've already chosen the best response.3dont worry i just learned this a couple of days ago i was frustrated too but i can help in this now:)

karatechopper
 5 years ago
Best ResponseYou've already chosen the best response.3r the parentheses supposed to be the absolute value signs? and is x2 x times 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the graph of y=2(x+3)^2+1 will have curvature downwards and its vertex is at \[(1/\sqrt{2}3.0)\]

karatechopper
 5 years ago
Best ResponseYou've already chosen the best response.3well i luckey has given answer so good job

karatechopper
 5 years ago
Best ResponseYou've already chosen the best response.3yea im proud of my self:) ROBIN AWAY!

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=2(x+3)^2+1 \text{ has vertex } (3,1)\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=a(xh)^2+k \text{ has vertex } (h,k)\] if a>0 then the parabola is concave up if a<0 then the parabola is concave down
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