## anonymous 5 years ago The graph of y = x2 is shown below. Using complete sentences, explain how the graph of y = –2(x + 3)2 + 1 would differ from this parabola?

1. anonymous

sorry..not a good artist..the vertex is (0,0)

2. anonymous

|dw:1322072661463:dw|

3. karatechopper

r u doing absolute valuee functions/equations?

4. anonymous

yes..I need hlep with this

5. karatechopper

dont worry i just learned this a couple of days ago i was frustrated too but i can help in this now:)

6. anonymous

thank you

7. karatechopper

r the parentheses supposed to be the absolute value signs? and is x2 x times 2?

8. anonymous

the graph of y=-2(x+3)^2+1 will have curvature downwards and its vertex is at $(1/\sqrt{2}-3.0)$

9. karatechopper

woah...^

10. anonymous

yes, and x2 is x^2

11. anonymous

thank you guyz

12. karatechopper

ok

13. karatechopper

well i luckey has given answer so good job

14. anonymous

U still tried

15. karatechopper

yea im proud of my self:) ROBIN AWAY!

16. karatechopper

thnx

17. myininaya

$y=-2(x+3)^2+1 \text{ has vertex } (-3,1)$

18. myininaya

$y=a(x-h)^2+k \text{ has vertex } (h,k)$ if a>0 then the parabola is concave up if a<0 then the parabola is concave down