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The graph of y = x2 is shown below. Using complete sentences, explain how the graph of y = –2(x + 3)2 + 1 would differ from this parabola?

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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sorry..not a good artist..the vertex is (0,0)
r u doing absolute valuee functions/equations?

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Other answers:

yes..I need hlep with this
dont worry i just learned this a couple of days ago i was frustrated too but i can help in this now:)
thank you
r the parentheses supposed to be the absolute value signs? and is x2 x times 2?
the graph of y=-2(x+3)^2+1 will have curvature downwards and its vertex is at \[(1/\sqrt{2}-3.0)\]
yes, and x2 is x^2
thank you guyz
well i luckey has given answer so good job
U still tried
yea im proud of my self:) ROBIN AWAY!
\[y=-2(x+3)^2+1 \text{ has vertex } (-3,1)\]
\[y=a(x-h)^2+k \text{ has vertex } (h,k)\] if a>0 then the parabola is concave up if a<0 then the parabola is concave down

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