anonymous
  • anonymous
The graph of y = x2 is shown below. Using complete sentences, explain how the graph of y = –2(x + 3)2 + 1 would differ from this parabola?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
sorry..not a good artist..the vertex is (0,0)
anonymous
  • anonymous
|dw:1322072661463:dw|
karatechopper
  • karatechopper
r u doing absolute valuee functions/equations?

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anonymous
  • anonymous
yes..I need hlep with this
karatechopper
  • karatechopper
dont worry i just learned this a couple of days ago i was frustrated too but i can help in this now:)
anonymous
  • anonymous
thank you
karatechopper
  • karatechopper
r the parentheses supposed to be the absolute value signs? and is x2 x times 2?
anonymous
  • anonymous
the graph of y=-2(x+3)^2+1 will have curvature downwards and its vertex is at \[(1/\sqrt{2}-3.0)\]
karatechopper
  • karatechopper
woah...^
anonymous
  • anonymous
yes, and x2 is x^2
anonymous
  • anonymous
thank you guyz
karatechopper
  • karatechopper
ok
karatechopper
  • karatechopper
well i luckey has given answer so good job
anonymous
  • anonymous
U still tried
karatechopper
  • karatechopper
yea im proud of my self:) ROBIN AWAY!
karatechopper
  • karatechopper
thnx
myininaya
  • myininaya
\[y=-2(x+3)^2+1 \text{ has vertex } (-3,1)\]
myininaya
  • myininaya
\[y=a(x-h)^2+k \text{ has vertex } (h,k)\] if a>0 then the parabola is concave up if a<0 then the parabola is concave down

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