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:/

oops

wait it's not radical it's rational

rational expressions

i learned when it's x^2 but not x^3

i mastered radical expressions by the way

take the x common in the numerator you get a quadratic equation which is what you know

by everything?

oh wait

\[\large{\frac{x^3-x^2-42x}{2x^2-20x+42}= \frac{x(x^2-x-42)}{2x^2-20x+42}}\]

oh i see, thanks!

Of course it can be simplified further

yes^

neverforgetvivistee should post her solution on here to make sure it is right

yes^

i got x(x+6)/2(x+3)

wait no it's x-3

x(x+6)/2(x-3)

yeah thats right

nice

i'll master rationals soon

GoodLuck ;)

thanks everyone