A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 3 years ago
adding rational expressions:
what do I do with the 3v that's hanging out?
(v2)
 + 3v
(3v^415v^318v^2)
I already factored the denominator
I got 3v^2(v6)(v+1),but I don't know what to do next
 3 years ago
adding rational expressions: what do I do with the 3v that's hanging out? (v2)  + 3v (3v^415v^318v^2) I already factored the denominator I got 3v^2(v6)(v+1),but I don't know what to do next

This Question is Closed

moneybird
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3v(3v^415v^318v^2)}{(3v^415v^318v^2)}\]

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0i multiply first? i thought i had to factor first?

Toader
 3 years ago
Best ResponseYou've already chosen the best response.1To add fractions, they need to have the same common denominator Multiply 3v by (3v^2(v6)(v+1))/(3v^2(v6)(v+1)) (this is technically equal to 1, so is allowed as it does not change the expression) You'll get: (v2) + 3v (3v^2(v6)(v+1))  3v^2(v6)(v+1) or (v2) + 9v^3(v6)(v+1)  3v^2(v6)(v+1) (This is keeping the denominator expression factored like you did, but is not really necessary as it doesn't help simplify anything else.

Toader
 3 years ago
Best ResponseYou've already chosen the best response.1First step after multiplying 3v by the common denominator is actually this, if you were curious. I skipped it (v2) 3v (3v^2(v6)(v+1)) +  3v^2(v6)(v+1) 3v^2(v6)(v+1)

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0i got 9v^3+6v^215v when i multiplied 3v and (3v^2(v6)(v+1

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0i did this wrong... i am looking at my multiplication

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0i'll redo it

Toader
 3 years ago
Best ResponseYou've already chosen the best response.1Think of \[3v^{2}(v6)(v+1)\] as three independent terms multiplied by eachother. You have \[3v^{2}\] \[(v6)\] and \[(v+1)\] Multiplying it by 3v is just sticking another term on there in the multiplication. making it \[(3v)3v^{2}(v6)(v+1)\] You can simplyfy this by combining it with \[3v^{2}\] making \[9v^{3}\]

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0what am i doing wrong here?? 3v * 3v^2 = 9v^3 3v * (v6) = 3v^218v 3v(v+1)= 9v^2+3v i get 9v^3+3v^218v+3v^2+3v then i combine like terms and i get 9v^3+6v^215v

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0derp i just multiplied it wrong, got it!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.