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neverforgetvivistee
Group Title
adding rational expressions:
what do I do with the 3v that's hanging out?
(v2)
 + 3v
(3v^415v^318v^2)
I already factored the denominator
I got 3v^2(v6)(v+1),but I don't know what to do next
 3 years ago
 3 years ago
neverforgetvivistee Group Title
adding rational expressions: what do I do with the 3v that's hanging out? (v2)  + 3v (3v^415v^318v^2) I already factored the denominator I got 3v^2(v6)(v+1),but I don't know what to do next
 3 years ago
 3 years ago

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moneybird Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{3v(3v^415v^318v^2)}{(3v^415v^318v^2)}\]
 3 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
i multiply first? i thought i had to factor first?
 3 years ago

Toader Group TitleBest ResponseYou've already chosen the best response.1
To add fractions, they need to have the same common denominator Multiply 3v by (3v^2(v6)(v+1))/(3v^2(v6)(v+1)) (this is technically equal to 1, so is allowed as it does not change the expression) You'll get: (v2) + 3v (3v^2(v6)(v+1))  3v^2(v6)(v+1) or (v2) + 9v^3(v6)(v+1)  3v^2(v6)(v+1) (This is keeping the denominator expression factored like you did, but is not really necessary as it doesn't help simplify anything else.
 3 years ago

Toader Group TitleBest ResponseYou've already chosen the best response.1
First step after multiplying 3v by the common denominator is actually this, if you were curious. I skipped it (v2) 3v (3v^2(v6)(v+1)) +  3v^2(v6)(v+1) 3v^2(v6)(v+1)
 3 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
i got 9v^3+6v^215v when i multiplied 3v and (3v^2(v6)(v+1
 3 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
i did this wrong... i am looking at my multiplication
 3 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
i'll redo it
 3 years ago

Toader Group TitleBest ResponseYou've already chosen the best response.1
Think of \[3v^{2}(v6)(v+1)\] as three independent terms multiplied by eachother. You have \[3v^{2}\] \[(v6)\] and \[(v+1)\] Multiplying it by 3v is just sticking another term on there in the multiplication. making it \[(3v)3v^{2}(v6)(v+1)\] You can simplyfy this by combining it with \[3v^{2}\] making \[9v^{3}\]
 3 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
what am i doing wrong here?? 3v * 3v^2 = 9v^3 3v * (v6) = 3v^218v 3v(v+1)= 9v^2+3v i get 9v^3+3v^218v+3v^2+3v then i combine like terms and i get 9v^3+6v^215v
 3 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
bump
 3 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
derp i just multiplied it wrong, got it!
 3 years ago
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