Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

neverforgetvivistee Group Title

adding rational expressions: what do I do with the 3v that's hanging out? (v-2) ----------------- + 3v (3v^4-15v^3-18v^2) I already factored the denominator I got 3v^2(v-6)(v+1),but I don't know what to do next

  • 3 years ago
  • 3 years ago

  • This Question is Closed
  1. moneybird Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{3v(3v^4-15v^3-18v^2)}{(3v^4-15v^3-18v^2)}\]

    • 3 years ago
  2. neverforgetvivistee Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i multiply first? i thought i had to factor first?

    • 3 years ago
  3. Toader Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    To add fractions, they need to have the same common denominator Multiply 3v by (3v^2(v-6)(v+1))/(3v^2(v-6)(v+1)) (this is technically equal to 1, so is allowed as it does not change the expression) You'll get: (v-2) + 3v (3v^2(v-6)(v+1)) --------------------------- 3v^2(v-6)(v+1) or (v-2) + 9v^3(v-6)(v+1) ---------------------- 3v^2(v-6)(v+1) (This is keeping the denominator expression factored like you did, but is not really necessary as it doesn't help simplify anything else.

    • 3 years ago
  4. Toader Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    First step after multiplying 3v by the common denominator is actually this, if you were curious. I skipped it (v-2) 3v (3v^2(v-6)(v+1)) ------------------+ ----------------- 3v^2(v-6)(v+1) 3v^2(v-6)(v+1)

    • 3 years ago
  5. neverforgetvivistee Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i got 9v^3+6v^2-15v when i multiplied 3v and (3v^2(v-6)(v+1

    • 3 years ago
  6. neverforgetvivistee Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i did this wrong... i am looking at my multiplication

    • 3 years ago
  7. neverforgetvivistee Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i'll redo it

    • 3 years ago
  8. Toader Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Think of \[3v^{2}(v-6)(v+1)\] as three independent terms multiplied by eachother. You have \[3v^{2}\] \[(v-6)\] and \[(v+1)\] Multiplying it by 3v is just sticking another term on there in the multiplication. making it \[(3v)3v^{2}(v-6)(v+1)\] You can simplyfy this by combining it with \[3v^{2}\] making \[9v^{3}\]

    • 3 years ago
  9. neverforgetvivistee Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    what am i doing wrong here?? 3v * 3v^2 = 9v^3 3v * (v-6) = 3v^2-18v 3v(v+1)= 9v^2+3v i get 9v^3+3v^2-18v+3v^2+3v then i combine like terms and i get 9v^3+6v^2-15v

    • 3 years ago
  10. neverforgetvivistee Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    bump

    • 3 years ago
  11. neverforgetvivistee Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    derp i just multiplied it wrong, got it!

    • 3 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.