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\[\frac{3v(3v^4-15v^3-18v^2)}{(3v^4-15v^3-18v^2)}\]

i multiply first? i thought i had to factor first?

i got 9v^3+6v^2-15v when i multiplied 3v and (3v^2(v-6)(v+1

i did this wrong... i am looking at my multiplication

i'll redo it

bump

derp i just multiplied it wrong, got it!