anonymous
  • anonymous
Solving rational equations: (2x+2) (4x^2-16) (5x-5) ------- - ---------- = -------------- (3x-12) (3x^2-24x+48) (3x^2-24x+48) I have the answer already, but I don't know how it came to be I try to do it by factoring the 3x^2-24x+48 's and get 3(x^2-8+16) then I multiply that by everything, as with the other denominators, and so on but then I get a huge, incorrect answer Someone please help even if it's one sentence. I want to get this problem done by tonight
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Firstly you can factor out a 3
anonymous
  • anonymous
and then it becomes 3(x-4)^2
anonymous
  • anonymous
and 3x-12 can also be factored

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anonymous
  • anonymous
3(x-4)
anonymous
  • anonymous
So from what I see in order to get the same denomanator you must multiply the denomanator and numerator by (x-4)
anonymous
  • anonymous
Did u get that so far
anonymous
  • anonymous
yes and i'm fixing it on my paper... stupid factoring mistakes Thanks!
anonymous
  • anonymous
ok gnite
anonymous
  • anonymous
after this problem goodnight
anonymous
  • anonymous
Do you multiply the numerator of the first fraction by 3(x-4)^4? This is where i messed up the most I was struggling with factoring because I'm half asleep if you were wondering why I took so long by the way...
anonymous
  • anonymous
nope you multiply the numerator and the denomanator of the first term by (x-4)
anonymous
  • anonymous
what about the 3?
anonymous
  • anonymous
because in the second fraction the denominator I get is 3(x-4)
anonymous
  • anonymous
well we already have a 3 in the denomanator of the first term
anonymous
  • anonymous
First term denomanator: 3(x-4) second term denomanator: 3(x-4) (x-4)
anonymous
  • anonymous
so all your missing in the first term is the (x-4)
anonymous
  • anonymous
how did you get rid of the 3?
anonymous
  • anonymous
I factored it
anonymous
  • anonymous
factor (3x-12) for me
anonymous
  • anonymous
3(x-4)
anonymous
  • anonymous
it is 3(x-4)
anonymous
  • anonymous
ya
anonymous
  • anonymous
so what doesn't make sense
anonymous
  • anonymous
when you're supposed to multiply everything by the denominator
anonymous
  • anonymous
nope we have two denomanators and we need them to be the same
anonymous
  • anonymous
so in order ofor 3(x-4) to be equal to 3(x-4)^2
anonymous
  • anonymous
we would have to multiply the first term by a (x-4)
anonymous
  • anonymous
so 3(x-4)*(x-4)=3(x-4)^2
anonymous
  • anonymous
Is that clear?
anonymous
  • anonymous
yes sort of , do we do that to the numerator too?
anonymous
  • anonymous
yup forsure
anonymous
  • anonymous
ooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh ok I see I see
anonymous
  • anonymous
YAY i am so excited
anonymous
  • anonymous
I try to explain concepts but sometimes the person on the other end can't understand
anonymous
  • anonymous
THANK YOU OK I ACTUALLY SEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! THANK YOU OK LISTEN TO ME RIGHT NOW LOOK AT YOURSELF IN THE MIRROR AND SAY HELL YEAH IM AWESOME IM SO GOOD AT MATH THANK YOU OKAY BECAUSE I WAS REALLY STRUGGLING WITH THAT AND NOW I CAN FINALLY SLEEP
anonymous
  • anonymous
NOW IM GOING TO FINISH THIS PROBLEM AND GET THE RIGHT ANSWER!!!!!!!!!!
anonymous
  • anonymous
Oh thanks for the boost I needed that one!!! LOL
anonymous
  • anonymous
lol
anonymous
  • anonymous
someone give rld613 some more medals
anonymous
  • anonymous
i'm going to solve this problem right now afk
anonymous
  • anonymous
I am really not into the medal thing
anonymous
  • anonymous
I just enjoy doing math
anonymous
  • anonymous
its like past 2 am and I am still doing math equations!!! I shld be long in bed
anonymous
  • anonymous
K now that we finished i am going to bed
anonymous
  • anonymous
rld are you still there?

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