Solving rational equations:
(2x+2) (4x^2-16) (5x-5)
------- - ---------- = --------------
(3x-12) (3x^2-24x+48) (3x^2-24x+48)
I have the answer already, but I don't know how it came to be
I try to do it by factoring the 3x^2-24x+48 's and get 3(x^2-8+16)
then I multiply that by everything, as with the other denominators, and so on
but then I get a huge, incorrect answer
Someone please help even if it's one sentence. I want to get this problem done by tonight

- anonymous

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- anonymous

Firstly you can factor out a 3

- anonymous

and then it becomes 3(x-4)^2

- anonymous

and 3x-12 can also be factored

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## More answers

- anonymous

3(x-4)

- anonymous

So from what I see in order to get the same denomanator you must multiply the denomanator and numerator by (x-4)

- anonymous

Did u get that so far

- anonymous

yes and i'm fixing it on my paper... stupid factoring mistakes
Thanks!

- anonymous

ok gnite

- anonymous

after this problem goodnight

- anonymous

Do you multiply the numerator of the first fraction by 3(x-4)^4?
This is where i messed up the most
I was struggling with factoring because I'm half asleep if you were wondering why I took so long by the way...

- anonymous

nope you multiply the numerator and the denomanator of the first term by (x-4)

- anonymous

what about the 3?

- anonymous

because in the second fraction the denominator I get is 3(x-4)

- anonymous

well we already have a 3 in the denomanator of the first term

- anonymous

First term denomanator: 3(x-4)
second term denomanator: 3(x-4) (x-4)

- anonymous

so all your missing in the first term is the (x-4)

- anonymous

how did you get rid of the 3?

- anonymous

I factored it

- anonymous

factor (3x-12) for me

- anonymous

3(x-4)

- anonymous

it is 3(x-4)

- anonymous

ya

- anonymous

so what doesn't make sense

- anonymous

when you're supposed to multiply everything by the denominator

- anonymous

nope we have two denomanators and we need them to be the same

- anonymous

so in order ofor 3(x-4) to be equal to 3(x-4)^2

- anonymous

we would have to multiply the first term by a (x-4)

- anonymous

so 3(x-4)*(x-4)=3(x-4)^2

- anonymous

Is that clear?

- anonymous

yes sort of , do we do that to the numerator too?

- anonymous

yup forsure

- anonymous

ooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh ok I see I see

- anonymous

YAY i am so excited

- anonymous

I try to explain concepts but sometimes the person on the other end can't understand

- anonymous

THANK YOU OK I ACTUALLY SEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! THANK YOU OK LISTEN TO ME RIGHT NOW LOOK AT YOURSELF IN THE MIRROR AND SAY HELL YEAH IM AWESOME IM SO GOOD AT MATH THANK YOU OKAY BECAUSE I WAS REALLY STRUGGLING WITH THAT AND NOW I CAN FINALLY SLEEP

- anonymous

NOW IM GOING TO FINISH THIS PROBLEM AND GET THE RIGHT ANSWER!!!!!!!!!!

- anonymous

Oh thanks for the boost I needed that one!!! LOL

- anonymous

lol

- anonymous

someone give rld613 some more medals

- anonymous

i'm going to solve this problem right now afk

- anonymous

I am really not into the medal thing

- anonymous

I just enjoy doing math

- anonymous

its like past 2 am and I am still doing math equations!!! I shld be long in bed

- anonymous

K now that we finished i am going to bed

- anonymous

rld are you still there?

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