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Firstly you can factor out a 3

and then it becomes 3(x-4)^2

and 3x-12 can also be factored

3(x-4)

Did u get that so far

yes and i'm fixing it on my paper... stupid factoring mistakes
Thanks!

ok gnite

after this problem goodnight

nope you multiply the numerator and the denomanator of the first term by (x-4)

what about the 3?

because in the second fraction the denominator I get is 3(x-4)

well we already have a 3 in the denomanator of the first term

First term denomanator: 3(x-4)
second term denomanator: 3(x-4) (x-4)

so all your missing in the first term is the (x-4)

how did you get rid of the 3?

I factored it

factor (3x-12) for me

3(x-4)

it is 3(x-4)

ya

so what doesn't make sense

when you're supposed to multiply everything by the denominator

nope we have two denomanators and we need them to be the same

so in order ofor 3(x-4) to be equal to 3(x-4)^2

we would have to multiply the first term by a (x-4)

so 3(x-4)*(x-4)=3(x-4)^2

Is that clear?

yes sort of , do we do that to the numerator too?

yup forsure

ooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh ok I see I see

YAY i am so excited

I try to explain concepts but sometimes the person on the other end can't understand

NOW IM GOING TO FINISH THIS PROBLEM AND GET THE RIGHT ANSWER!!!!!!!!!!

Oh thanks for the boost I needed that one!!! LOL

lol

someone give rld613 some more medals

i'm going to solve this problem right now afk

I am really not into the medal thing

I just enjoy doing math

its like past 2 am and I am still doing math equations!!! I shld be long in bed

K now that we finished i am going to bed

rld are you still there?