neverforgetvivistee 4 years ago Solving rational equations: (2x+2) (4x^2-16) (5x-5) ------- - ---------- = -------------- (3x-12) (3x^2-24x+48) (3x^2-24x+48) I have the answer already, but I don't know how it came to be I try to do it by factoring the 3x^2-24x+48 's and get 3(x^2-8+16) then I multiply that by everything, as with the other denominators, and so on but then I get a huge, incorrect answer Someone please help even if it's one sentence. I want to get this problem done by tonight

1. rld613

Firstly you can factor out a 3

2. rld613

and then it becomes 3(x-4)^2

3. rld613

and 3x-12 can also be factored

4. rld613

3(x-4)

5. rld613

So from what I see in order to get the same denomanator you must multiply the denomanator and numerator by (x-4)

6. rld613

Did u get that so far

7. neverforgetvivistee

yes and i'm fixing it on my paper... stupid factoring mistakes Thanks!

8. rld613

ok gnite

9. neverforgetvivistee

after this problem goodnight

10. neverforgetvivistee

Do you multiply the numerator of the first fraction by 3(x-4)^4? This is where i messed up the most I was struggling with factoring because I'm half asleep if you were wondering why I took so long by the way...

11. rld613

nope you multiply the numerator and the denomanator of the first term by (x-4)

12. neverforgetvivistee

13. neverforgetvivistee

because in the second fraction the denominator I get is 3(x-4)

14. rld613

well we already have a 3 in the denomanator of the first term

15. rld613

First term denomanator: 3(x-4) second term denomanator: 3(x-4) (x-4)

16. rld613

so all your missing in the first term is the (x-4)

17. neverforgetvivistee

how did you get rid of the 3?

18. rld613

I factored it

19. rld613

factor (3x-12) for me

20. neverforgetvivistee

3(x-4)

21. rld613

it is 3(x-4)

22. rld613

ya

23. rld613

so what doesn't make sense

24. neverforgetvivistee

when you're supposed to multiply everything by the denominator

25. rld613

nope we have two denomanators and we need them to be the same

26. rld613

so in order ofor 3(x-4) to be equal to 3(x-4)^2

27. rld613

we would have to multiply the first term by a (x-4)

28. rld613

so 3(x-4)*(x-4)=3(x-4)^2

29. rld613

Is that clear?

30. neverforgetvivistee

yes sort of , do we do that to the numerator too?

31. rld613

yup forsure

32. neverforgetvivistee

ooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh ok I see I see

33. rld613

YAY i am so excited

34. rld613

I try to explain concepts but sometimes the person on the other end can't understand

35. neverforgetvivistee

THANK YOU OK I ACTUALLY SEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! THANK YOU OK LISTEN TO ME RIGHT NOW LOOK AT YOURSELF IN THE MIRROR AND SAY HELL YEAH IM AWESOME IM SO GOOD AT MATH THANK YOU OKAY BECAUSE I WAS REALLY STRUGGLING WITH THAT AND NOW I CAN FINALLY SLEEP

36. neverforgetvivistee

NOW IM GOING TO FINISH THIS PROBLEM AND GET THE RIGHT ANSWER!!!!!!!!!!

37. rld613

Oh thanks for the boost I needed that one!!! LOL

38. neverforgetvivistee

lol

39. neverforgetvivistee

someone give rld613 some more medals

40. neverforgetvivistee

i'm going to solve this problem right now afk

41. rld613

I am really not into the medal thing

42. rld613

I just enjoy doing math

43. rld613

its like past 2 am and I am still doing math equations!!! I shld be long in bed

44. rld613

K now that we finished i am going to bed

45. neverforgetvivistee

rld are you still there?