Solving rational equations:
(2x+2) (4x^2-16) (5x-5)
------- - ---------- = --------------
(3x-12) (3x^2-24x+48) (3x^2-24x+48)
I have the answer already, but I don't know how it came to be
I try to do it by factoring the 3x^2-24x+48 's and get 3(x^2-8+16)
then I multiply that by everything, as with the other denominators, and so on
but then I get a huge, incorrect answer
Someone please help even if it's one sentence. I want to get this problem done by tonight

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Firstly you can factor out a 3

and then it becomes 3(x-4)^2

and 3x-12 can also be factored

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