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neverforgetvivistee Group Title

Solving rational equations: (2x+2) (4x^2-16) (5x-5) ------- - ---------- = -------------- (3x-12) (3x^2-24x+48) (3x^2-24x+48) I have the answer already, but I don't know how it came to be I try to do it by factoring the 3x^2-24x+48 's and get 3(x^2-8+16) then I multiply that by everything, as with the other denominators, and so on but then I get a huge, incorrect answer Someone please help even if it's one sentence. I want to get this problem done by tonight

  • 3 years ago
  • 3 years ago

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  1. rld613 Group Title
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    Firstly you can factor out a 3

    • 3 years ago
  2. rld613 Group Title
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    and then it becomes 3(x-4)^2

    • 3 years ago
  3. rld613 Group Title
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    and 3x-12 can also be factored

    • 3 years ago
  4. rld613 Group Title
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    3(x-4)

    • 3 years ago
  5. rld613 Group Title
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    So from what I see in order to get the same denomanator you must multiply the denomanator and numerator by (x-4)

    • 3 years ago
  6. rld613 Group Title
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    Did u get that so far

    • 3 years ago
  7. neverforgetvivistee Group Title
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    yes and i'm fixing it on my paper... stupid factoring mistakes Thanks!

    • 3 years ago
  8. rld613 Group Title
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    ok gnite

    • 3 years ago
  9. neverforgetvivistee Group Title
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    after this problem goodnight

    • 3 years ago
  10. neverforgetvivistee Group Title
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    Do you multiply the numerator of the first fraction by 3(x-4)^4? This is where i messed up the most I was struggling with factoring because I'm half asleep if you were wondering why I took so long by the way...

    • 3 years ago
  11. rld613 Group Title
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    nope you multiply the numerator and the denomanator of the first term by (x-4)

    • 3 years ago
  12. neverforgetvivistee Group Title
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    what about the 3?

    • 3 years ago
  13. neverforgetvivistee Group Title
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    because in the second fraction the denominator I get is 3(x-4)

    • 3 years ago
  14. rld613 Group Title
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    well we already have a 3 in the denomanator of the first term

    • 3 years ago
  15. rld613 Group Title
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    First term denomanator: 3(x-4) second term denomanator: 3(x-4) (x-4)

    • 3 years ago
  16. rld613 Group Title
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    so all your missing in the first term is the (x-4)

    • 3 years ago
  17. neverforgetvivistee Group Title
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    how did you get rid of the 3?

    • 3 years ago
  18. rld613 Group Title
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    I factored it

    • 3 years ago
  19. rld613 Group Title
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    factor (3x-12) for me

    • 3 years ago
  20. neverforgetvivistee Group Title
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    3(x-4)

    • 3 years ago
  21. rld613 Group Title
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    it is 3(x-4)

    • 3 years ago
  22. rld613 Group Title
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    ya

    • 3 years ago
  23. rld613 Group Title
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    so what doesn't make sense

    • 3 years ago
  24. neverforgetvivistee Group Title
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    when you're supposed to multiply everything by the denominator

    • 3 years ago
  25. rld613 Group Title
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    nope we have two denomanators and we need them to be the same

    • 3 years ago
  26. rld613 Group Title
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    so in order ofor 3(x-4) to be equal to 3(x-4)^2

    • 3 years ago
  27. rld613 Group Title
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    we would have to multiply the first term by a (x-4)

    • 3 years ago
  28. rld613 Group Title
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    so 3(x-4)*(x-4)=3(x-4)^2

    • 3 years ago
  29. rld613 Group Title
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    Is that clear?

    • 3 years ago
  30. neverforgetvivistee Group Title
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    yes sort of , do we do that to the numerator too?

    • 3 years ago
  31. rld613 Group Title
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    yup forsure

    • 3 years ago
  32. neverforgetvivistee Group Title
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    ooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh ok I see I see

    • 3 years ago
  33. rld613 Group Title
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    YAY i am so excited

    • 3 years ago
  34. rld613 Group Title
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    I try to explain concepts but sometimes the person on the other end can't understand

    • 3 years ago
  35. neverforgetvivistee Group Title
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    THANK YOU OK I ACTUALLY SEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! THANK YOU OK LISTEN TO ME RIGHT NOW LOOK AT YOURSELF IN THE MIRROR AND SAY HELL YEAH IM AWESOME IM SO GOOD AT MATH THANK YOU OKAY BECAUSE I WAS REALLY STRUGGLING WITH THAT AND NOW I CAN FINALLY SLEEP

    • 3 years ago
  36. neverforgetvivistee Group Title
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    NOW IM GOING TO FINISH THIS PROBLEM AND GET THE RIGHT ANSWER!!!!!!!!!!

    • 3 years ago
  37. rld613 Group Title
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    Oh thanks for the boost I needed that one!!! LOL

    • 3 years ago
  38. neverforgetvivistee Group Title
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    lol

    • 3 years ago
  39. neverforgetvivistee Group Title
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    someone give rld613 some more medals

    • 3 years ago
  40. neverforgetvivistee Group Title
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    i'm going to solve this problem right now afk

    • 3 years ago
  41. rld613 Group Title
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    I am really not into the medal thing

    • 3 years ago
  42. rld613 Group Title
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    I just enjoy doing math

    • 3 years ago
  43. rld613 Group Title
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    its like past 2 am and I am still doing math equations!!! I shld be long in bed

    • 3 years ago
  44. rld613 Group Title
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    K now that we finished i am going to bed

    • 3 years ago
  45. neverforgetvivistee Group Title
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    rld are you still there?

    • 3 years ago
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