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\[x=\sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1+...}}}}}...\]

\[x^2-x = 1 => x(x-1) = 1\]

now i feel u can solve it

yeah but how u got the x2 thing equation

ok btw options are x=1, 0

sorry x-1 = 1
x = 2

and x = 1

so which option

1

yes i too feel so

ok thnx

welcome :)

hmm good question

yeah sheg is right

thnx help in my next question pls

it converges to 1.75487766625 so the value of x should be in the range 1 < x < 2