King
  • King
its a sqrt question so i shall post it as a reply
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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King
  • King
\[x=\sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1+...}}}}}...\]
anonymous
  • anonymous
\[x^2-x = 1 => x(x-1) = 1\]
anonymous
  • anonymous
now i feel u can solve it

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King
  • King
yeah but how u got the x2 thing equation
King
  • King
ok btw options are x=1, 0
anonymous
  • anonymous
see x is having number of sqrt that is upto infinity so let us take \[x = \sqrt{1+x}\] square both sides u will get \[x^2 = 1 + x\]
anonymous
  • anonymous
sorry x-1 = 1 x = 2
anonymous
  • anonymous
and x = 1
King
  • King
so which option
King
  • King
1
anonymous
  • anonymous
yes i too feel so
King
  • King
ok thnx
anonymous
  • anonymous
welcome :)
anonymous
  • anonymous
hmm good question
anonymous
  • anonymous
yeah sheg is right
King
  • King
thnx help in my next question pls
anonymous
  • anonymous
it converges to 1.75487766625 so the value of x should be in the range 1 < x < 2

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