## neverforgetvivistee 3 years ago Can you simplify this further? *Using the quadratic formula to factor x^2-6x-4* The answer is supposed to be 6(+-)√53 / 2 ,but can't you simplify by 2? 6 and 2 go into 2. Then could it be 3(+-)√68/1 or no?

1. Hero

Hi neverforgettovisitme

2. neverforgetvivistee

hi

3. neverforgetvivistee

lol

4. moneybird

6(+-)√53 / 2 is simplified

5. Hero

:D

6. Tomas.A

answer is is $3\pm\sqrt{13}$

7. neverforgetvivistee

wait how is it simplified? in another problem there was a problem where you divided by 3 because it was a common factor

8. neverforgetvivistee

wait i'll go look for it

9. neverforgetvivistee

-9x^2-9x+6

10. satellite73

no you cannot because the number inside the radical contains no perfect squares. this is the best you can do

11. neverforgetvivistee

later in the problem the guy got 9(+-)3√33 --------- -18 then he simplified by 3

12. neverforgetvivistee

13. satellite73

for $-9x^2-9x+6=0$ you can start with $3x^2+3x-2=0$ and reduce before you start

14. neverforgetvivistee

oh i see

15. satellite73

hold the phone solution to $x^2-6x-4=0$is not what you wrote. it is what tomas A wrote

16. Tomas.A

$\frac{9\pm3\sqrt{33}}{-18}=$ you can simplify this since $\frac{3(3\pm\sqrt{33})}{-6\cdot3}=$ $\frac{1(3\pm\sqrt{33})}{-6\cdot1}=$

17. satellite73

$x^2-6x-4=0$ $x^2-6x=4$ $(x-3)^2=4+9=13$ $x-3=\pm\sqrt{13}$ $x=3\pm\sqrt{13}$