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neverforgetvivistee Group Title

Can you simplify this further? *Using the quadratic formula to factor x^2-6x-4* The answer is supposed to be 6(+-)√53 / 2 ,but can't you simplify by 2? 6 and 2 go into 2. Then could it be 3(+-)√68/1 or no?

  • 2 years ago
  • 2 years ago

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  1. Hero Group Title
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    Hi neverforgettovisitme

    • 2 years ago
  2. neverforgetvivistee Group Title
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    hi

    • 2 years ago
  3. neverforgetvivistee Group Title
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    lol

    • 2 years ago
  4. moneybird Group Title
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    6(+-)√53 / 2 is simplified

    • 2 years ago
  5. Hero Group Title
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    :D

    • 2 years ago
  6. Tomas.A Group Title
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    answer is is \[3\pm\sqrt{13}\]

    • 2 years ago
  7. neverforgetvivistee Group Title
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    wait how is it simplified? in another problem there was a problem where you divided by 3 because it was a common factor

    • 2 years ago
  8. neverforgetvivistee Group Title
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    wait i'll go look for it

    • 2 years ago
  9. neverforgetvivistee Group Title
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    -9x^2-9x+6

    • 2 years ago
  10. satellite73 Group Title
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    no you cannot because the number inside the radical contains no perfect squares. this is the best you can do

    • 2 years ago
  11. neverforgetvivistee Group Title
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    later in the problem the guy got 9(+-)3√33 --------- -18 then he simplified by 3

    • 2 years ago
  12. neverforgetvivistee Group Title
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    khanacademy

    • 2 years ago
  13. satellite73 Group Title
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    for \[-9x^2-9x+6=0\] you can start with \[3x^2+3x-2=0\] and reduce before you start

    • 2 years ago
  14. neverforgetvivistee Group Title
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    oh i see

    • 2 years ago
  15. satellite73 Group Title
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    hold the phone solution to \[ x^2-6x-4=0\]is not what you wrote. it is what tomas A wrote

    • 2 years ago
  16. Tomas.A Group Title
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    \[\frac{9\pm3\sqrt{33}}{-18}=\] you can simplify this since \[\frac{3(3\pm\sqrt{33})}{-6\cdot3}=\] \[\frac{1(3\pm\sqrt{33})}{-6\cdot1}=\]

    • 2 years ago
  17. satellite73 Group Title
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    \[x^2-6x-4=0\] \[x^2-6x=4\] \[(x-3)^2=4+9=13\] \[x-3=\pm\sqrt{13}\] \[x=3\pm\sqrt{13}\]

    • 2 years ago
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