## neverforgetvivistee Group Title Can you simplify this further? *Using the quadratic formula to factor x^2-6x-4* The answer is supposed to be 6(+-)√53 / 2 ,but can't you simplify by 2? 6 and 2 go into 2. Then could it be 3(+-)√68/1 or no? 2 years ago 2 years ago

1. Hero Group Title

Hi neverforgettovisitme

2. neverforgetvivistee Group Title

hi

3. neverforgetvivistee Group Title

lol

4. moneybird Group Title

6(+-)√53 / 2 is simplified

5. Hero Group Title

:D

6. Tomas.A Group Title

answer is is $3\pm\sqrt{13}$

7. neverforgetvivistee Group Title

wait how is it simplified? in another problem there was a problem where you divided by 3 because it was a common factor

8. neverforgetvivistee Group Title

wait i'll go look for it

9. neverforgetvivistee Group Title

-9x^2-9x+6

10. satellite73 Group Title

no you cannot because the number inside the radical contains no perfect squares. this is the best you can do

11. neverforgetvivistee Group Title

later in the problem the guy got 9(+-)3√33 --------- -18 then he simplified by 3

12. neverforgetvivistee Group Title

13. satellite73 Group Title

for $-9x^2-9x+6=0$ you can start with $3x^2+3x-2=0$ and reduce before you start

14. neverforgetvivistee Group Title

oh i see

15. satellite73 Group Title

hold the phone solution to $x^2-6x-4=0$is not what you wrote. it is what tomas A wrote

16. Tomas.A Group Title

$\frac{9\pm3\sqrt{33}}{-18}=$ you can simplify this since $\frac{3(3\pm\sqrt{33})}{-6\cdot3}=$ $\frac{1(3\pm\sqrt{33})}{-6\cdot1}=$

17. satellite73 Group Title

$x^2-6x-4=0$ $x^2-6x=4$ $(x-3)^2=4+9=13$ $x-3=\pm\sqrt{13}$ $x=3\pm\sqrt{13}$