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Can you simplify this further? *Using the quadratic formula to factor x^2-6x-4* The answer is supposed to be 6(+-)√53 / 2 ,but can't you simplify by 2? 6 and 2 go into 2. Then could it be 3(+-)√68/1 or no?

Mathematics
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Hi neverforgettovisitme
hi
lol

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Other answers:

6(+-)√53 / 2 is simplified
:D
answer is is \[3\pm\sqrt{13}\]
wait how is it simplified? in another problem there was a problem where you divided by 3 because it was a common factor
wait i'll go look for it
-9x^2-9x+6
no you cannot because the number inside the radical contains no perfect squares. this is the best you can do
later in the problem the guy got 9(+-)3√33 --------- -18 then he simplified by 3
khanacademy
for \[-9x^2-9x+6=0\] you can start with \[3x^2+3x-2=0\] and reduce before you start
oh i see
hold the phone solution to \[ x^2-6x-4=0\]is not what you wrote. it is what tomas A wrote
\[\frac{9\pm3\sqrt{33}}{-18}=\] you can simplify this since \[\frac{3(3\pm\sqrt{33})}{-6\cdot3}=\] \[\frac{1(3\pm\sqrt{33})}{-6\cdot1}=\]
\[x^2-6x-4=0\] \[x^2-6x=4\] \[(x-3)^2=4+9=13\] \[x-3=\pm\sqrt{13}\] \[x=3\pm\sqrt{13}\]

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