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anonymous
 5 years ago
Can you simplify this further?
*Using the quadratic formula to factor x^26x4*
The answer is supposed to be 6(+)√53 / 2 ,but can't you simplify by 2? 6 and 2 go into 2.
Then could it be 3(+)√68/1
or no?
anonymous
 5 years ago
Can you simplify this further? *Using the quadratic formula to factor x^26x4* The answer is supposed to be 6(+)√53 / 2 ,but can't you simplify by 2? 6 and 2 go into 2. Then could it be 3(+)√68/1 or no?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.06(+)√53 / 2 is simplified

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0answer is is \[3\pm\sqrt{13}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait how is it simplified? in another problem there was a problem where you divided by 3 because it was a common factor

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait i'll go look for it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no you cannot because the number inside the radical contains no perfect squares. this is the best you can do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0later in the problem the guy got 9(+)3√33  18 then he simplified by 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for \[9x^29x+6=0\] you can start with \[3x^2+3x2=0\] and reduce before you start

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hold the phone solution to \[ x^26x4=0\]is not what you wrote. it is what tomas A wrote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{9\pm3\sqrt{33}}{18}=\] you can simplify this since \[\frac{3(3\pm\sqrt{33})}{6\cdot3}=\] \[\frac{1(3\pm\sqrt{33})}{6\cdot1}=\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^26x4=0\] \[x^26x=4\] \[(x3)^2=4+9=13\] \[x3=\pm\sqrt{13}\] \[x=3\pm\sqrt{13}\]
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