Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

neverforgetvivistee

  • 3 years ago

solving rational equations: x+2 x - 1 4x+2 ---- = ---- - ----- x x x^2-3x I know how to make them all have a common denominator x(x-3) but when it comes to solving I get x^2+5x+6=x^2-4x-3x-3x-2 which then comes up to be x^2+3x-11 This isn't right. What did I do wrong?

  • This Question is Closed
  1. satellite73
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    maybe it would be easier to multiply both sides by \[x(x-3)\]

  2. neverforgetvivistee
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i did

  3. neverforgetvivistee
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but i can't figure out what i did wrong because i get the wrong answer... when i multiply x+2 and x-3 i get x^2+5x+5 when i multiply x-1 and x-3 i get x^2-4x-3

  4. satellite73
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you get \[(x+2)(x-3)=(x-1)(x-3)-4x+2\] i htink

  5. satellite73
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hold on \[(x+2)(x-3)=x^2-x-6\] ,maybe that is the mistake

  6. satellite73
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    also \[(x-1)(x-3)=x^2-4x+3\]

  7. neverforgetvivistee
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh!!!!!! i put (x+2) and postive (x+3)!!

  8. neverforgetvivistee
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that was a waste of time i was looking just at how i solved it and not how i multiplied it. Thanks

  9. satellite73
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[(x+2)(x-3)=(x-1)(x-3)-4x+2\] \[x^2-x-6=x^2-4x+3-4x+2\] \[x^2-x-6=x^2-8x+5\] etc

  10. satellite73
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yw

  11. neverforgetvivistee
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative? for examples x-1 4x+2 ---- - ----- x(x-3) x(x-3) would you make it into a plus sign, and then make 4x and 2 negative? -4x-2

  12. neverforgetvivistee
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    bump

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.