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neverforgetvivistee
 3 years ago
solving rational equations:
x+2 x  1 4x+2
 =   
x x x^23x
I know how to make them all have a common denominator x(x3)
but when it comes to solving I get
x^2+5x+6=x^24x3x3x2
which then comes up to be x^2+3x11
This isn't right. What did I do wrong?
neverforgetvivistee
 3 years ago
solving rational equations: x+2 x  1 4x+2  =    x x x^23x I know how to make them all have a common denominator x(x3) but when it comes to solving I get x^2+5x+6=x^24x3x3x2 which then comes up to be x^2+3x11 This isn't right. What did I do wrong?

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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2maybe it would be easier to multiply both sides by \[x(x3)\]

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0but i can't figure out what i did wrong because i get the wrong answer... when i multiply x+2 and x3 i get x^2+5x+5 when i multiply x1 and x3 i get x^24x3

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2you get \[(x+2)(x3)=(x1)(x3)4x+2\] i htink

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2hold on \[(x+2)(x3)=x^2x6\] ,maybe that is the mistake

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2also \[(x1)(x3)=x^24x+3\]

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0oh!!!!!! i put (x+2) and postive (x+3)!!

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0that was a waste of time i was looking just at how i solved it and not how i multiplied it. Thanks

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2\[(x+2)(x3)=(x1)(x3)4x+2\] \[x^2x6=x^24x+34x+2\] \[x^2x6=x^28x+5\] etc

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative? for examples x1 4x+2    x(x3) x(x3) would you make it into a plus sign, and then make 4x and 2 negative? 4x2
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