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anonymous
 5 years ago
when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative?
for examples
x1 4x+2
  
x(x3) x(x3)
would you make it into a plus sign, and then make 4x and 2 negative?
4x2
anonymous
 5 years ago
when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative? for examples x1 4x+2    x(x3) x(x3) would you make it into a plus sign, and then make 4x and 2 negative? 4x2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the other equation you did how did you get positive 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the last one you answered

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x1(4x+2)}{x(x3)}\] \[\frac{x14x2}{x(x3)}\] etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well in the last one you caught me in a dumb algebra mistake that is why!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0should be \[\frac{x+2}{x}=\frac{x1}{x}\frac{4x+2}{x(x3)}\] \[(x+2)(x3)=(x1)(x+3)4x2\] \[x^2x6 = x^22 x5\] \[x6=2x5\] \[x=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait what? i get x^2x6=x^28x+1 i keep on looking it over but i can't figure it out darn it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh man did i mess up again? hold on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so, (x3) and (x+2) equal x^2x6. (x1) and (x3) euqlas x^24x+3. then when i combine them x^2x6=x^24x+3x4x2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok now you have caught me in two mistakes, so i am going to quit. you are right it is \[(x+2)(x3)=(x1)(x3)4x2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then i combine like terms and get x^2x6=x^28x+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no please don't this is a very confusing problem lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok but i am making mistake after mistake. lets see what we get now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you get \[x^2x6 = x^28 x+1\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok subtract \[x^2\] from both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me know what you get

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what happened to your equal sign?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh wait let me do this again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^2x6 = x^28 x+1\] \[\cancel{x^2}x6=\cancel{x^2}8x+1\] \[x6=8x+1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I GOT THE RIGHT ANSWER THANK YOU!!!!!!!!!!!!!! FINALLY THIS PROBLEM IS THE WORST THANK YOU!!!!!!!!!!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yw. now i have a question. what is vivistee?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0listen thanks alright? my gosh that problem was so confusing and frustrating

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's finally over now :"}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm going to write that one down in my notes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0glad you got it, sorry about your cat
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