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neverforgetvivistee

  • 3 years ago

when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative? for examples x-1 4x+2 ---- - ----- x(x-3) x(x-3) would you make it into a plus sign, and then make 4x and 2 negative? -4x-2

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  1. satellite73
    • 3 years ago
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    yes

  2. neverforgetvivistee
    • 3 years ago
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    in the other equation you did how did you get positive 2?

  3. neverforgetvivistee
    • 3 years ago
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    the last one you answered

  4. satellite73
    • 3 years ago
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    \[\frac{x-1-(4x+2)}{x(x-3)}\] \[\frac{x-1-4x-2}{x(x-3)}\] etc

  5. satellite73
    • 3 years ago
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    well in the last one you caught me in a dumb algebra mistake that is why!

  6. satellite73
    • 3 years ago
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    should be \[\frac{x+2}{x}=\frac{x-1}{x}-\frac{4x+2}{x(x-3)}\] \[(x+2)(x-3)=(x-1)(x+3)-4x-2\] \[x^2-x-6 = x^2-2 x-5\] \[-x-6=-2x-5\] \[x=1\]

  7. neverforgetvivistee
    • 3 years ago
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    wait what? i get x^2-x-6=x^2-8x+1 i keep on looking it over but i can't figure it out darn it

  8. satellite73
    • 3 years ago
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    oh man did i mess up again? hold on

  9. neverforgetvivistee
    • 3 years ago
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    ok so, (x-3) and (x+2) equal x^2-x-6. (x-1) and (x-3) euqlas x^2-4x+3. then when i combine them x^2-x-6=x^2-4x+3x-4x-2

  10. satellite73
    • 3 years ago
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    ok now you have caught me in two mistakes, so i am going to quit. you are right it is \[(x+2)(x-3)=(x-1)(x-3)-4x-2\]

  11. neverforgetvivistee
    • 3 years ago
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    then i combine like terms and get x^2-x-6=x^2-8x+1

  12. neverforgetvivistee
    • 3 years ago
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    no please don't this is a very confusing problem lol

  13. neverforgetvivistee
    • 3 years ago
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    then i get 2x^1+7x+7

  14. satellite73
    • 3 years ago
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    ok but i am making mistake after mistake. lets see what we get now

  15. neverforgetvivistee
    • 3 years ago
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    i mean 2x^2+7x+7

  16. satellite73
    • 3 years ago
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    did you get \[x^2-x-6 = x^2-8 x+1\]?

  17. neverforgetvivistee
    • 3 years ago
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    yes

  18. satellite73
    • 3 years ago
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    ok subtract \[x^2\] from both sides

  19. satellite73
    • 3 years ago
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    let me know what you get

  20. neverforgetvivistee
    • 3 years ago
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    7x+7

  21. satellite73
    • 3 years ago
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    what happened to your equal sign?

  22. neverforgetvivistee
    • 3 years ago
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    0=7x+7

  23. neverforgetvivistee
    • 3 years ago
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    oh wait let me do this again

  24. neverforgetvivistee
    • 3 years ago
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    OMFG

  25. satellite73
    • 3 years ago
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    \[x^2-x-6 = x^2-8 x+1\] \[\cancel{x^2}-x-6=\cancel{x^2}-8x+1\] \[-x-6=-8x+1\]

  26. neverforgetvivistee
    • 3 years ago
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    I GOT THE RIGHT ANSWER THANK YOU!!!!!!!!!!!!!! FINALLY THIS PROBLEM IS THE WORST THANK YOU!!!!!!!!!!!!!

  27. neverforgetvivistee
    • 3 years ago
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    YES!!!!!!!!!

  28. neverforgetvivistee
    • 3 years ago
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    took forever!!!!!!!

  29. neverforgetvivistee
    • 3 years ago
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    x=1

  30. satellite73
    • 3 years ago
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    yw. now i have a question. what is vivistee?

  31. neverforgetvivistee
    • 3 years ago
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    my cat that ran away

  32. neverforgetvivistee
    • 3 years ago
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    never forget

  33. neverforgetvivistee
    • 3 years ago
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    listen thanks alright? my gosh that problem was so confusing and frustrating

  34. neverforgetvivistee
    • 3 years ago
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    :"}

  35. neverforgetvivistee
    • 3 years ago
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    it's finally over now :"}

  36. neverforgetvivistee
    • 3 years ago
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    i'm going to write that one down in my notes

  37. satellite73
    • 3 years ago
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    glad you got it, sorry about your cat

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