Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative? for examples x-1 4x+2 ---- - ----- x(x-3) x(x-3) would you make it into a plus sign, and then make 4x and 2 negative? -4x-2

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

yes
in the other equation you did how did you get positive 2?
the last one you answered

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[\frac{x-1-(4x+2)}{x(x-3)}\] \[\frac{x-1-4x-2}{x(x-3)}\] etc
well in the last one you caught me in a dumb algebra mistake that is why!
should be \[\frac{x+2}{x}=\frac{x-1}{x}-\frac{4x+2}{x(x-3)}\] \[(x+2)(x-3)=(x-1)(x+3)-4x-2\] \[x^2-x-6 = x^2-2 x-5\] \[-x-6=-2x-5\] \[x=1\]
wait what? i get x^2-x-6=x^2-8x+1 i keep on looking it over but i can't figure it out darn it
oh man did i mess up again? hold on
ok so, (x-3) and (x+2) equal x^2-x-6. (x-1) and (x-3) euqlas x^2-4x+3. then when i combine them x^2-x-6=x^2-4x+3x-4x-2
ok now you have caught me in two mistakes, so i am going to quit. you are right it is \[(x+2)(x-3)=(x-1)(x-3)-4x-2\]
then i combine like terms and get x^2-x-6=x^2-8x+1
no please don't this is a very confusing problem lol
then i get 2x^1+7x+7
ok but i am making mistake after mistake. lets see what we get now
i mean 2x^2+7x+7
did you get \[x^2-x-6 = x^2-8 x+1\]?
yes
ok subtract \[x^2\] from both sides
let me know what you get
7x+7
what happened to your equal sign?
0=7x+7
oh wait let me do this again
OMFG
\[x^2-x-6 = x^2-8 x+1\] \[\cancel{x^2}-x-6=\cancel{x^2}-8x+1\] \[-x-6=-8x+1\]
I GOT THE RIGHT ANSWER THANK YOU!!!!!!!!!!!!!! FINALLY THIS PROBLEM IS THE WORST THANK YOU!!!!!!!!!!!!!
YES!!!!!!!!!
took forever!!!!!!!
x=1
yw. now i have a question. what is vivistee?
my cat that ran away
never forget
listen thanks alright? my gosh that problem was so confusing and frustrating
:"}
it's finally over now :"}
i'm going to write that one down in my notes
glad you got it, sorry about your cat

Not the answer you are looking for?

Search for more explanations.

Ask your own question