anonymous
  • anonymous
when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative? for examples x-1 4x+2 ---- - ----- x(x-3) x(x-3) would you make it into a plus sign, and then make 4x and 2 negative? -4x-2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
yes
anonymous
  • anonymous
in the other equation you did how did you get positive 2?
anonymous
  • anonymous
the last one you answered

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anonymous
  • anonymous
\[\frac{x-1-(4x+2)}{x(x-3)}\] \[\frac{x-1-4x-2}{x(x-3)}\] etc
anonymous
  • anonymous
well in the last one you caught me in a dumb algebra mistake that is why!
anonymous
  • anonymous
should be \[\frac{x+2}{x}=\frac{x-1}{x}-\frac{4x+2}{x(x-3)}\] \[(x+2)(x-3)=(x-1)(x+3)-4x-2\] \[x^2-x-6 = x^2-2 x-5\] \[-x-6=-2x-5\] \[x=1\]
anonymous
  • anonymous
wait what? i get x^2-x-6=x^2-8x+1 i keep on looking it over but i can't figure it out darn it
anonymous
  • anonymous
oh man did i mess up again? hold on
anonymous
  • anonymous
ok so, (x-3) and (x+2) equal x^2-x-6. (x-1) and (x-3) euqlas x^2-4x+3. then when i combine them x^2-x-6=x^2-4x+3x-4x-2
anonymous
  • anonymous
ok now you have caught me in two mistakes, so i am going to quit. you are right it is \[(x+2)(x-3)=(x-1)(x-3)-4x-2\]
anonymous
  • anonymous
then i combine like terms and get x^2-x-6=x^2-8x+1
anonymous
  • anonymous
no please don't this is a very confusing problem lol
anonymous
  • anonymous
then i get 2x^1+7x+7
anonymous
  • anonymous
ok but i am making mistake after mistake. lets see what we get now
anonymous
  • anonymous
i mean 2x^2+7x+7
anonymous
  • anonymous
did you get \[x^2-x-6 = x^2-8 x+1\]?
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok subtract \[x^2\] from both sides
anonymous
  • anonymous
let me know what you get
anonymous
  • anonymous
7x+7
anonymous
  • anonymous
what happened to your equal sign?
anonymous
  • anonymous
0=7x+7
anonymous
  • anonymous
oh wait let me do this again
anonymous
  • anonymous
OMFG
anonymous
  • anonymous
\[x^2-x-6 = x^2-8 x+1\] \[\cancel{x^2}-x-6=\cancel{x^2}-8x+1\] \[-x-6=-8x+1\]
anonymous
  • anonymous
I GOT THE RIGHT ANSWER THANK YOU!!!!!!!!!!!!!! FINALLY THIS PROBLEM IS THE WORST THANK YOU!!!!!!!!!!!!!
anonymous
  • anonymous
YES!!!!!!!!!
anonymous
  • anonymous
took forever!!!!!!!
anonymous
  • anonymous
x=1
anonymous
  • anonymous
yw. now i have a question. what is vivistee?
anonymous
  • anonymous
my cat that ran away
anonymous
  • anonymous
never forget
anonymous
  • anonymous
listen thanks alright? my gosh that problem was so confusing and frustrating
anonymous
  • anonymous
:"}
anonymous
  • anonymous
it's finally over now :"}
anonymous
  • anonymous
i'm going to write that one down in my notes
anonymous
  • anonymous
glad you got it, sorry about your cat

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