when you're subtracting rationals, do you make it into a plus sign and make EVERYTHING in the numerator of the second negative, or just make 1 number negative?
for examples
x-1 4x+2
---- - -----
x(x-3) x(x-3)
would you make it into a plus sign, and then make 4x and 2 negative?
-4x-2

- anonymous

- jamiebookeater

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- anonymous

yes

- anonymous

in the other equation you did how did you get positive 2?

- anonymous

the last one you answered

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## More answers

- anonymous

\[\frac{x-1-(4x+2)}{x(x-3)}\]
\[\frac{x-1-4x-2}{x(x-3)}\] etc

- anonymous

well in the last one you caught me in a dumb algebra mistake that is why!

- anonymous

should be
\[\frac{x+2}{x}=\frac{x-1}{x}-\frac{4x+2}{x(x-3)}\]
\[(x+2)(x-3)=(x-1)(x+3)-4x-2\]
\[x^2-x-6 = x^2-2 x-5\]
\[-x-6=-2x-5\]
\[x=1\]

- anonymous

wait what? i get x^2-x-6=x^2-8x+1
i keep on looking it over but i can't figure it out darn it

- anonymous

oh man did i mess up again? hold on

- anonymous

ok so,
(x-3) and (x+2) equal x^2-x-6.
(x-1) and (x-3) euqlas x^2-4x+3.
then when i combine them
x^2-x-6=x^2-4x+3x-4x-2

- anonymous

ok now you have caught me in two mistakes, so i am going to quit.
you are right it is
\[(x+2)(x-3)=(x-1)(x-3)-4x-2\]

- anonymous

then i combine like terms and get x^2-x-6=x^2-8x+1

- anonymous

no please don't this is a very confusing problem lol

- anonymous

then i get 2x^1+7x+7

- anonymous

ok but i am making mistake after mistake. lets see what we get now

- anonymous

i mean 2x^2+7x+7

- anonymous

did you get
\[x^2-x-6 = x^2-8 x+1\]?

- anonymous

yes

- anonymous

ok subtract
\[x^2\] from both sides

- anonymous

let me know what you get

- anonymous

7x+7

- anonymous

what happened to your equal sign?

- anonymous

0=7x+7

- anonymous

oh wait let me do this again

- anonymous

OMFG

- anonymous

\[x^2-x-6 = x^2-8 x+1\]
\[\cancel{x^2}-x-6=\cancel{x^2}-8x+1\]
\[-x-6=-8x+1\]

- anonymous

I GOT THE RIGHT ANSWER THANK YOU!!!!!!!!!!!!!! FINALLY THIS PROBLEM IS THE WORST THANK YOU!!!!!!!!!!!!!

- anonymous

YES!!!!!!!!!

- anonymous

took forever!!!!!!!

- anonymous

x=1

- anonymous

yw. now i have a question. what is vivistee?

- anonymous

my cat that ran away

- anonymous

never forget

- anonymous

listen thanks alright? my gosh that problem was so confusing and frustrating

- anonymous

:"}

- anonymous

it's finally over now :"}

- anonymous

i'm going to write that one down in my notes

- anonymous

glad you got it, sorry about your cat

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