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yes

in the other equation you did how did you get positive 2?

the last one you answered

\[\frac{x-1-(4x+2)}{x(x-3)}\]
\[\frac{x-1-4x-2}{x(x-3)}\] etc

well in the last one you caught me in a dumb algebra mistake that is why!

wait what? i get x^2-x-6=x^2-8x+1
i keep on looking it over but i can't figure it out darn it

oh man did i mess up again? hold on

then i combine like terms and get x^2-x-6=x^2-8x+1

no please don't this is a very confusing problem lol

then i get 2x^1+7x+7

ok but i am making mistake after mistake. lets see what we get now

i mean 2x^2+7x+7

did you get
\[x^2-x-6 = x^2-8 x+1\]?

yes

ok subtract
\[x^2\] from both sides

let me know what you get

7x+7

what happened to your equal sign?

0=7x+7

oh wait let me do this again

OMFG

\[x^2-x-6 = x^2-8 x+1\]
\[\cancel{x^2}-x-6=\cancel{x^2}-8x+1\]
\[-x-6=-8x+1\]

YES!!!!!!!!!

took forever!!!!!!!

x=1

yw. now i have a question. what is vivistee?

my cat that ran away

never forget

listen thanks alright? my gosh that problem was so confusing and frustrating

:"}

it's finally over now :"}

i'm going to write that one down in my notes

glad you got it, sorry about your cat