King
  • King
Its a log problem which has sqrt so i shall post in reply...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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King
  • King
\[\log_{4} \sqrt[4]{32\sqrt[3]{16\sqrt{64.8^{-3\div4}}}}\]
anonymous
  • anonymous
2^5 = 32 2^4 = 16 Is it 64 x 8? or 64.8
King
  • King
its 64 x 8^-3/4

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King
  • King
please give full explanation
anonymous
  • anonymous
2^3 = 8 2^6 = 64 Now try it
anonymous
  • anonymous
I don't like this problem
King
  • King
wait even i dont like it
anonymous
  • anonymous
It's not hard but it's unnecessary
King
  • King
its necessary for me
anonymous
  • anonymous
1.019
King
  • King
i am not getting it can u xplain
anonymous
  • anonymous
oh cool sheg
King
  • King
no sheg answer is wrong
anonymous
  • anonymous
how come plz explain m right
King
  • King
idk answer given as 121/186 or 0.6505376
anonymous
  • anonymous
ok wait i made one mistake now i got it
anonymous
  • anonymous
I am getting .7 after simplifying and calculating it in the calculator
King
  • King
do not use claculator
King
  • King
and explain
King
  • King
u should get it as 121/186
anonymous
  • anonymous
King It's a big waste of time, it's not worth it
King
  • King
pls ishaan its necessary fr me
King
  • King
sheg wat abt u?
anonymous
  • anonymous
trying to solve it manually
anonymous
  • anonymous
Hmm I am not posting the complete solution, Just a little simplification \[\frac{1}{4} \left(\log_4 32 + \frac{1}{3}\left(\log_416 + \frac{1}{2}\left(\log_4 64 + \log_4 8^{\frac{-3}{4}} \right)\right)\right)\]
anonymous
  • anonymous
is that 64 times 8?????????????
anonymous
  • anonymous
Now you should do it on your own, I really don't like calculating Numbers
King
  • King
how did u get 1/4
King
  • King
yeah sheg
anonymous
  • anonymous
oh got i was taking 64.8
anonymous
  • anonymous
Yeah Sheg
anonymous
  • anonymous
Read the FIITJEE Module for Logs it's the basic property of Log
anonymous
  • anonymous
nahi yar mein usko decimal mein le raha tha na bracket use kiya hai isne na kuch
King
  • King
wait im reading and i gave u this sum from FIITJEE compendium
King
  • King
sry sheg are u now getting right answer?
anonymous
  • anonymous
Hmm mujhe bhi same confusion hua tha
anonymous
  • anonymous
i m getting this thing \[\log_{4} 2^{\frac{167}{96}}\]
King
  • King
what is that 2^?
anonymous
  • anonymous
167/96
King
  • King
thats 0.8 sumthing...
King
  • King
ishaan i calculated ure equation i got 29/32
anonymous
  • anonymous
you must have calculated it wrong
King
  • King
wait i am checking for mistake
anonymous
  • anonymous
I am getting 127/192 I hate this problem, I hate calculating numbers
anonymous
  • anonymous
.661458333 <
King
  • King
u need to subtract 6 frm numerator and denom. to get rite answer so thatt means u are very close
KatrinaKaif
  • KatrinaKaif
Took me forever to get to the bottom of this >.>
King
  • King
so post solution katrina
King
  • King
ishaan what is simplified version of log8^-3/4 base4
anonymous
  • anonymous
\[\log_4\sqrt[4]{32\sqrt[3]{16\sqrt{64\cdot8^{-\frac{3}{4}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\sqrt{2^6\cdot2^{-\frac{9}{4}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\sqrt{2^{\frac{15}{4}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\cdot{2^{\frac{15}{8}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{{2^{\frac{47}{8}}}}}=\] \[\log_4\sqrt[4]{2^5\cdot{{2^{\frac{47}{24}}}}}=\] \[\log_4\sqrt[4]{{{2^{\frac{167}{24}}}}}=\] \[\log_{2^2}2^{\frac{167}{96}}=\] \[\log_{2}2^{\frac{167}{192}}=\] \[\frac{167}{192}\]
anonymous
  • anonymous
Yeah I did it again I am getting the same
King
  • King
can u explain the 4th step
King
  • King
how did u take out 2^15/4?
anonymous
  • anonymous
\[2^4\cdot2^{\frac{15}{8}}=2^{4+\frac{15}{8}}=2^{\frac{32}{8}+\frac{15}{8}}=2^{\frac{47}{8}}\] this one?
King
  • King
no how did u take 2^15/4 out frm sqrt
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=log_4%28%2832+*+%2816+*%2864+*+8^%28-3%2F4%29%29^%281%2F2%29%29^%281%2F3%29%29^%281%2F4%29 Tomas Is Right, FIITJEE is wrong!
King
  • King
ok now can u xplain
anonymous
  • anonymous
\[\sqrt{2^\frac{15}{4}}=2^{\frac{15}{4}\cdot\frac{1}{2}}=2^\frac{15}{8}\]
King
  • King
oh right
anonymous
  • anonymous
\[\sqrt[n]{m}=m^{\frac{1}{n}}\]
King
  • King
Yipppeeeeeeeee u guys are great!!!!!!!!!! thnx to all of u.!!!!!!!!!!!!!!!

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