At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

\[\log_{4} \sqrt[4]{32\sqrt[3]{16\sqrt{64.8^{-3\div4}}}}\]

2^5 = 32
2^4 = 16
Is it 64 x 8? or 64.8

its 64 x 8^-3/4

please give full explanation

2^3 = 8
2^6 = 64
Now try it

I don't like this problem

wait even i dont like it

It's not hard but it's unnecessary

its necessary for me

1.019

i am not getting it can u xplain

oh cool sheg

no sheg answer is wrong

how come plz explain m right

idk answer given as 121/186 or 0.6505376

ok wait i made one mistake now i got it

I am getting .7 after simplifying and calculating it in the calculator

do not use claculator

and explain

u should get it as 121/186

King It's a big waste of time, it's not worth it

pls ishaan its necessary fr me

sheg wat abt u?

trying to solve it manually

is that 64 times 8?????????????

Now you should do it on your own, I really don't like calculating Numbers

how did u get 1/4

yeah sheg

oh got i was taking 64.8

Yeah Sheg

Read the FIITJEE Module for Logs it's the basic property of Log

nahi yar mein usko decimal mein le raha tha na bracket use kiya hai isne na kuch

wait im reading and i gave u this sum from FIITJEE compendium

sry sheg are u now getting right answer?

Hmm mujhe bhi same confusion hua tha

i m getting this thing
\[\log_{4} 2^{\frac{167}{96}}\]

what is that 2^?

167/96

thats 0.8 sumthing...

ishaan i calculated ure equation i got 29/32

you must have calculated it wrong

wait i am checking for mistake

I am getting 127/192 I hate this problem, I hate calculating numbers

.661458333 <

u need to subtract 6 frm numerator and denom. to get rite answer so thatt means u are very close

Took me forever to get to the bottom of this >.>

so post solution katrina

ishaan what is simplified version of log8^-3/4 base4

Yeah I did it again I am getting the same

can u explain the 4th step

how did u take out 2^15/4?

no how did u take 2^15/4 out frm sqrt

ok now can u xplain

\[\sqrt{2^\frac{15}{4}}=2^{\frac{15}{4}\cdot\frac{1}{2}}=2^\frac{15}{8}\]

oh right

\[\sqrt[n]{m}=m^{\frac{1}{n}}\]

Yipppeeeeeeeee u guys are great!!!!!!!!!!
thnx to all of u.!!!!!!!!!!!!!!!