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King
 5 years ago
Its a log problem which has sqrt so i shall post in reply...
King
 5 years ago
Its a log problem which has sqrt so i shall post in reply...

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King
 5 years ago
Best ResponseYou've already chosen the best response.1\[\log_{4} \sqrt[4]{32\sqrt[3]{16\sqrt{64.8^{3\div4}}}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02^5 = 32 2^4 = 16 Is it 64 x 8? or 64.8

King
 5 years ago
Best ResponseYou've already chosen the best response.1please give full explanation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02^3 = 8 2^6 = 64 Now try it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't like this problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's not hard but it's unnecessary

King
 5 years ago
Best ResponseYou've already chosen the best response.1i am not getting it can u xplain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how come plz explain m right

King
 5 years ago
Best ResponseYou've already chosen the best response.1idk answer given as 121/186 or 0.6505376

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok wait i made one mistake now i got it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am getting .7 after simplifying and calculating it in the calculator

King
 5 years ago
Best ResponseYou've already chosen the best response.1u should get it as 121/186

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0King It's a big waste of time, it's not worth it

King
 5 years ago
Best ResponseYou've already chosen the best response.1pls ishaan its necessary fr me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0trying to solve it manually

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm I am not posting the complete solution, Just a little simplification \[\frac{1}{4} \left(\log_4 32 + \frac{1}{3}\left(\log_416 + \frac{1}{2}\left(\log_4 64 + \log_4 8^{\frac{3}{4}} \right)\right)\right)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that 64 times 8?????????????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now you should do it on your own, I really don't like calculating Numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh got i was taking 64.8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Read the FIITJEE Module for Logs it's the basic property of Log

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nahi yar mein usko decimal mein le raha tha na bracket use kiya hai isne na kuch

King
 5 years ago
Best ResponseYou've already chosen the best response.1wait im reading and i gave u this sum from FIITJEE compendium

King
 5 years ago
Best ResponseYou've already chosen the best response.1sry sheg are u now getting right answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm mujhe bhi same confusion hua tha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i m getting this thing \[\log_{4} 2^{\frac{167}{96}}\]

King
 5 years ago
Best ResponseYou've already chosen the best response.1ishaan i calculated ure equation i got 29/32

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you must have calculated it wrong

King
 5 years ago
Best ResponseYou've already chosen the best response.1wait i am checking for mistake

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am getting 127/192 I hate this problem, I hate calculating numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0.661458333 <<Calculator

King
 5 years ago
Best ResponseYou've already chosen the best response.1u need to subtract 6 frm numerator and denom. to get rite answer so thatt means u are very close

KatrinaKaif
 5 years ago
Best ResponseYou've already chosen the best response.0Took me forever to get to the bottom of this >.>

King
 5 years ago
Best ResponseYou've already chosen the best response.1ishaan what is simplified version of log8^3/4 base4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\log_4\sqrt[4]{32\sqrt[3]{16\sqrt{64\cdot8^{\frac{3}{4}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\sqrt{2^6\cdot2^{\frac{9}{4}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\sqrt{2^{\frac{15}{4}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\cdot{2^{\frac{15}{8}}}}}=\] \[\log_4\sqrt[4]{2^5\sqrt[3]{{2^{\frac{47}{8}}}}}=\] \[\log_4\sqrt[4]{2^5\cdot{{2^{\frac{47}{24}}}}}=\] \[\log_4\sqrt[4]{{{2^{\frac{167}{24}}}}}=\] \[\log_{2^2}2^{\frac{167}{96}}=\] \[\log_{2}2^{\frac{167}{192}}=\] \[\frac{167}{192}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah I did it again I am getting the same

King
 5 years ago
Best ResponseYou've already chosen the best response.1can u explain the 4th step

King
 5 years ago
Best ResponseYou've already chosen the best response.1how did u take out 2^15/4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2^4\cdot2^{\frac{15}{8}}=2^{4+\frac{15}{8}}=2^{\frac{32}{8}+\frac{15}{8}}=2^{\frac{47}{8}}\] this one?

King
 5 years ago
Best ResponseYou've already chosen the best response.1no how did u take 2^15/4 out frm sqrt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=log_4%28%2832+*+%2816+*%2864+*+8^%283%2F4%29%29^%281%2F2%29%29^%281%2F3%29%29^%281%2F4%29 Tomas Is Right, FIITJEE is wrong!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2^\frac{15}{4}}=2^{\frac{15}{4}\cdot\frac{1}{2}}=2^\frac{15}{8}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[n]{m}=m^{\frac{1}{n}}\]

King
 5 years ago
Best ResponseYou've already chosen the best response.1Yipppeeeeeeeee u guys are great!!!!!!!!!! thnx to all of u.!!!!!!!!!!!!!!!
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