Expand and simplify the first 3 terms of the binomal power: (3y+5)^9 PLEASE HELP!!

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Expand and simplify the first 3 terms of the binomal power: (3y+5)^9 PLEASE HELP!!

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Do you know the binomial theorem? It lets you find the nth term of insane expressions like this. :)
I know usually how to solve using the pascal's triangle, but I don't know how to do it for just the first 3 terms
http://regentsprep.org/Regents/math/algtrig/ATP4/bintheorem.htm might be useful.

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Check out the examples. Then substitute your numbers in and see what happens. NOTE -- you will get BIG NUMBERS.
Okay, that was useful, but we're not supposed to be using the formula for this question. Do you know if there's any way to solve it just using pascal's triangle?
You'd have to expand out to the 9th row! Have fun with that! Fortunately you can do it in excel. :) http://jwilson.coe.uga.edu/EMAT6680/Parsons/MVP6690/Essay1/excel.html
use the binomial coefficients \[{n\choose r}=\frac{n!}{r!(n-r)!}\]

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