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patbatE21
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{\pi/2}secx dx\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2because \[\sec(\frac{\pi}{2})\] is undefined

patbatE21
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2} ((x)/(x^2 5x +6)) dx\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2since \[\sec(x)=\frac{1}{\cos(x)}\]and \[\cos(\frac{\pi}{2})=0\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2second one because the denominator is zero at x = 2

patbatE21
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{infinite}^{0} ((1)/(x^2 +5)) dx\]

patbatE21
 3 years ago
Best ResponseYou've already chosen the best response.0So the first one can be called a infinite discontinuity I'm guessing
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