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patbatE21Best ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{\pi/2}secx dx\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.2
because \[\sec(\frac{\pi}{2})\] is undefined
 2 years ago

patbatE21Best ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{2} ((x)/(x^2 5x +6)) dx\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.2
since \[\sec(x)=\frac{1}{\cos(x)}\]and \[\cos(\frac{\pi}{2})=0\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.2
second one because the denominator is zero at x = 2
 2 years ago

patbatE21Best ResponseYou've already chosen the best response.0
\[\int\limits_{infinite}^{0} ((1)/(x^2 +5)) dx\]
 2 years ago

patbatE21Best ResponseYou've already chosen the best response.0
So the first one can be called a infinite discontinuity I'm guessing
 2 years ago
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