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neverforgetvivistee
Group Title
can someone please help me in understanding graphing quadratic inequalities?
look at this (answers are below)
http://www.kutasoftware.com/FreeWorksheets/Alg1Worksheets/Graphing%20Quadratic%20Inequalities.pdf
what does the solid/shaded line mean? Why is it shaded in and some are shaded out? I know how to get the coordinates by plugging in random x values, but I don't know about anything else.
 2 years ago
 2 years ago
neverforgetvivistee Group Title
can someone please help me in understanding graphing quadratic inequalities? look at this (answers are below) http://www.kutasoftware.com/FreeWorksheets/Alg1Worksheets/Graphing%20Quadratic%20Inequalities.pdf what does the solid/shaded line mean? Why is it shaded in and some are shaded out? I know how to get the coordinates by plugging in random x values, but I don't know about anything else.
 2 years ago
 2 years ago

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asnaseer Group TitleBest ResponseYou've already chosen the best response.1
ok, in general, lets say you have some function in the form:\[y=f(x)\]and you have some inequality like:\[y>=4\]
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
now, on the line \(y=f(x)\) you know the value of 'y' will EQUAL the value of 'f(x)', so we draw the curve for y=f(x) as a solid line to indicate that we need to include this region.
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
so now we need to consider the line y=4. this will be a horizontal line which passes through y=4.
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
the horizontal line could intersect the curve at some points. e.g.: dw:1322436287068:dw
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
now since our inequality is y>=4, we need to draw a solid line at the places where y=4.
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
dw:1322436426127:dw
 2 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
but what about the shaded region?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
sorry  my explanation went a bit hay wire above!
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
what I should have said is lets say we have an inequality of the form y>=f(x)
 2 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
lol it's okay take your time :)
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
now, on the curve y=f(x), we know it satisfies the inequality  so we make the line solid
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
below the curve y=f(x) does NOT satisfy the inequality as there we have y<f(x)
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
above the curve y=f(x) DOES satisfy the inequality, so we include that region by shading it in
 2 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
for shading it in, how do you know it satisfies the inequality?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
dw:1322436711384:dw
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
does the diagram make sense?
 2 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
not really :(
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
I have taken some point x=x1 (which is represented by the vertical line) where this vertical line crosses the curve y=f(x), we know y=f(x1) above that point of intersection, we know y>f(x1) below that point of intersection, we know y<f(x1)
 2 years ago

neverforgetvivistee Group TitleBest ResponseYou've already chosen the best response.0
thanks :)
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
np  sorry for the confusion at the beginning :)
 2 years ago
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