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neverforgetvivistee
 3 years ago
can someone please help me in understanding graphing quadratic inequalities?
look at this (answers are below)
http://www.kutasoftware.com/FreeWorksheets/Alg1Worksheets/Graphing%20Quadratic%20Inequalities.pdf
what does the solid/shaded line mean? Why is it shaded in and some are shaded out? I know how to get the coordinates by plugging in random x values, but I don't know about anything else.
neverforgetvivistee
 3 years ago
can someone please help me in understanding graphing quadratic inequalities? look at this (answers are below) http://www.kutasoftware.com/FreeWorksheets/Alg1Worksheets/Graphing%20Quadratic%20Inequalities.pdf what does the solid/shaded line mean? Why is it shaded in and some are shaded out? I know how to get the coordinates by plugging in random x values, but I don't know about anything else.

This Question is Closed

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1ok, in general, lets say you have some function in the form:\[y=f(x)\]and you have some inequality like:\[y>=4\]

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1now, on the line \(y=f(x)\) you know the value of 'y' will EQUAL the value of 'f(x)', so we draw the curve for y=f(x) as a solid line to indicate that we need to include this region.

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1so now we need to consider the line y=4. this will be a horizontal line which passes through y=4.

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1the horizontal line could intersect the curve at some points. e.g.: dw:1322436287068:dw

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1now since our inequality is y>=4, we need to draw a solid line at the places where y=4.

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0but what about the shaded region?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1sorry  my explanation went a bit hay wire above!

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1what I should have said is lets say we have an inequality of the form y>=f(x)

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0lol it's okay take your time :)

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1now, on the curve y=f(x), we know it satisfies the inequality  so we make the line solid

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1below the curve y=f(x) does NOT satisfy the inequality as there we have y<f(x)

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1above the curve y=f(x) DOES satisfy the inequality, so we include that region by shading it in

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0for shading it in, how do you know it satisfies the inequality?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1does the diagram make sense?

neverforgetvivistee
 3 years ago
Best ResponseYou've already chosen the best response.0not really :(

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1I have taken some point x=x1 (which is represented by the vertical line) where this vertical line crosses the curve y=f(x), we know y=f(x1) above that point of intersection, we know y>f(x1) below that point of intersection, we know y<f(x1)

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.1np  sorry for the confusion at the beginning :)
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