At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

what problem exactly do you have with this integral?

well the I'm actually trying to sketch a region enclosed by given curves

but i think there is something wrong with my integration...so far I have 9y -1/3y^3 -1/2y^2 - y

first off I assume you mean (9 - x^2 - x -1)dx

yes

so then you answer is correct if you replace y's with x's

y = x + 1, y = 9 - x^2, x = -1, x = 2

I am just having issues finding the area

let's just do the integral first, yeah?

ok

I know that I will have to take the integral [f(y) -g(y)] from c to d

I believe that is my problem, understood

so your integral is\[\int\limits_{-1}^{2}9-x^2-x-1dx\]

Alright, I'm so far

19.2

let me try! lol

lol ok

Thank you so much

wait a minute this is all wrong! I should have noticed sooner!

No its correct I just submitted it online and it is marked correct

yes thats correct

I see what you mean, but how is it still correct

Ok, the ah-hah moments in math...such a wonderful subject

Thanks once again

very welcome!