## rld613 4 years ago lim e^t -t^n as t approaches infinity

1. rld613

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2. rld613

where n is a positive interger

3. rld613

thanks for coming

4. rld613

plz help me

5. rld613

it is 3:30 and I wanna go to bed

6. Denebel

infinity

7. rld613

can u explain how u got that?

8. Denebel

Because to find the limit of the two, you find the limit of each one individually (e^t) and (t^n). you can plug anything into n, like 5. the limit for$e^\infty$ is infinity. (look at an e^x graph) and limit for $\infty^5$ will be infinity

9. rld613

so it is infinity -infinity

10. Denebel

yeah, poor diction, I know. yes.

11. rld613

so what wld the answer be then?

12. Denebel

$\infty$ because an exponential function increases more rapidly than a function (?)

13. rld613

oh true so it wld be infinity. C my book never told me this part!!!!

14. Denebel

sorry, bad at mathematical terminology; if you weren't in a rush I'd Google the right term for it. basically the (e^x) will grow faster than the (t^n) so the limit will be infinity

15. rld613

ya i guess the term wld be dominance?

16. kirbykirby

this works to infinity though if n>0

17. rld613

yes and this is so

18. kirbykirby

actually it should still be in finity of we had a negative o_O

19. kirbykirby

ya i dont think you can do this one otherwise than looking at the function's 'growth rates"

20. rld613

infinity is not a limit so i guess there is no limit

21. kirbykirby

yes infinity is a limit

22. rld613

oh ok. Thanks. i appreciate ur help

23. rld613

Gnite ;-)

24. kirbykirby

if you had like cos(pi*n) as n->infinity then you can say there is none because it keeps oscillating between -1 and 1

25. rld613

oh i see

26. rld613

thanks e/o who helped out I really appreciate it