anonymous
  • anonymous
lim e^t -t^n as t approaches infinity
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1322468149480:dw|
anonymous
  • anonymous
where n is a positive interger
anonymous
  • anonymous
thanks for coming

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anonymous
  • anonymous
plz help me
anonymous
  • anonymous
it is 3:30 and I wanna go to bed
anonymous
  • anonymous
infinity
anonymous
  • anonymous
can u explain how u got that?
anonymous
  • anonymous
Because to find the limit of the two, you find the limit of each one individually (e^t) and (t^n). you can plug anything into n, like 5. the limit for\[e^\infty\] is infinity. (look at an e^x graph) and limit for \[\infty^5\] will be infinity
anonymous
  • anonymous
so it is infinity -infinity
anonymous
  • anonymous
yeah, poor diction, I know. yes.
anonymous
  • anonymous
so what wld the answer be then?
anonymous
  • anonymous
\[\infty\] because an exponential function increases more rapidly than a function (?)
anonymous
  • anonymous
oh true so it wld be infinity. C my book never told me this part!!!!
anonymous
  • anonymous
sorry, bad at mathematical terminology; if you weren't in a rush I'd Google the right term for it. basically the (e^x) will grow faster than the (t^n) so the limit will be infinity
anonymous
  • anonymous
ya i guess the term wld be dominance?
kirbykirby
  • kirbykirby
this works to infinity though if n>0
anonymous
  • anonymous
yes and this is so
kirbykirby
  • kirbykirby
actually it should still be in finity of we had a negative o_O
kirbykirby
  • kirbykirby
ya i dont think you can do this one otherwise than looking at the function's 'growth rates"
anonymous
  • anonymous
infinity is not a limit so i guess there is no limit
kirbykirby
  • kirbykirby
yes infinity is a limit
anonymous
  • anonymous
oh ok. Thanks. i appreciate ur help
anonymous
  • anonymous
Gnite ;-)
kirbykirby
  • kirbykirby
if you had like cos(pi*n) as n->infinity then you can say there is none because it keeps oscillating between -1 and 1
anonymous
  • anonymous
oh i see
anonymous
  • anonymous
thanks e/o who helped out I really appreciate it

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