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rld613 Group TitleBest ResponseYou've already chosen the best response.0
dw:1322468149480:dw
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
where n is a positive interger
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
thanks for coming
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
it is 3:30 and I wanna go to bed
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
can u explain how u got that?
 3 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Because to find the limit of the two, you find the limit of each one individually (e^t) and (t^n). you can plug anything into n, like 5. the limit for\[e^\infty\] is infinity. (look at an e^x graph) and limit for \[\infty^5\] will be infinity
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
so it is infinity infinity
 3 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
yeah, poor diction, I know. yes.
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
so what wld the answer be then?
 3 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
\[\infty\] because an exponential function increases more rapidly than a function (?)
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
oh true so it wld be infinity. C my book never told me this part!!!!
 3 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
sorry, bad at mathematical terminology; if you weren't in a rush I'd Google the right term for it. basically the (e^x) will grow faster than the (t^n) so the limit will be infinity
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
ya i guess the term wld be dominance?
 3 years ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.0
this works to infinity though if n>0
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
yes and this is so
 3 years ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.0
actually it should still be in finity of we had a negative o_O
 3 years ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.0
ya i dont think you can do this one otherwise than looking at the function's 'growth rates"
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
infinity is not a limit so i guess there is no limit
 3 years ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.0
yes infinity is a limit
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
oh ok. Thanks. i appreciate ur help
 3 years ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.0
if you had like cos(pi*n) as n>infinity then you can say there is none because it keeps oscillating between 1 and 1
 3 years ago

rld613 Group TitleBest ResponseYou've already chosen the best response.0
thanks e/o who helped out I really appreciate it
 3 years ago
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