A community for students.
Here's the question you clicked on:
 0 viewing
giggles123
 4 years ago
Find the function f given that it satisfies f''(x)=36x^2+24x
and its graph has a horizontal tangent line at the point (0,1)
giggles123
 4 years ago
Find the function f given that it satisfies f''(x)=36x^2+24x and its graph has a horizontal tangent line at the point (0,1)

This Question is Closed

Tyler1992
 4 years ago
Best ResponseYou've already chosen the best response.1Find the antiderivative 2 times.. So first \[f \prime (x) = 12x^3 + 12x^2 + C\]

giggles123
 4 years ago
Best ResponseYou've already chosen the best response.0f''(x)=3x^4+4x^3+c then what?

Tyler1992
 4 years ago
Best ResponseYou've already chosen the best response.1\[f(x) = 3x^4 + 4x^3 + Cx + D\]

giggles123
 4 years ago
Best ResponseYou've already chosen the best response.0Question is how do I find D?

Tyler1992
 4 years ago
Best ResponseYou've already chosen the best response.1We need to find what Cx and what D is.. Im trying to think how to do that

Tyler1992
 4 years ago
Best ResponseYou've already chosen the best response.1Right which would make Cx = 1

Tyler1992
 4 years ago
Best ResponseYou've already chosen the best response.1So we have \[f(x) = 3x^4 + 4x^3 + x + D\]

Tyler1992
 4 years ago
Best ResponseYou've already chosen the best response.1I ment it would make C = 1.. not Cx

giggles123
 4 years ago
Best ResponseYou've already chosen the best response.0if you do that you graph does not have a horizontal tangent line at (0,1) So c=1

giggles123
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you thou but I think I new how to do it.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.