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IN A TRIANGLE

for basic trig ratios it does

i think. draw a picture and show me your triangle

|dw:1322533988575:dw|

sin C

what's an easy way to figure out the opposite or adjacent?

opposite is across from the angle and adjacent is the sides touching the angle.

but they're both touching the angle

but that's the hypotenuse?

opposite and adjacent sides are both touching the angle

oo. sry

That was a bad example. \(\overline{BC}\) is not touching \(\angle BAC\).

what?

yakeyglee can you explain it for 5 year olds because i don't get what you typed

please come back PLEASE!!!

Do you see how \(\overline{BC}\) is NOT touching \(\angle BAC\)?

|dw:1322534541597:dw| like this?

Correct!

yes... but how do you know that bend part is the opposite? what about the other side where C is?

|dw:1322534666075:dw|

That one is adjacent to \(\overline{BC}\) because it literally lies right next to \(\overline{BC}\).

Whereas \(\angle BAC\) does not.

so bc is where your angle lies? why not ba?

why is bca important? is it because it has the hypotenuse?

No, because it's an angle in the triangle that's not the right-angle!

huh?? what about bac?

please don't give up on me :( i have a huge test tomorrow and i'll get an F if i don't get this

The labeled angle in that image would be your \(\theta\).