I have the following information:
\[n=p^2q\]
\[k \ge 4\]
\[0

Mathematics
- myininaya

I have the following information:
\[n=p^2q\]
\[k \ge 4\]
\[0

Mathematics
- Stacey Warren - Expert brainly.com

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- jamiebookeater

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- anonymous

i can't even read this
what class?

- myininaya

i made a mistake
\[\sum_{i=0}^{k}\left(\begin{matrix} k \\ i \end{matrix}\right) x^{k-i}(ypq)^i \equiv x^k+kypqx^{k-1}\]
I'm trying to follow a proof
but i don't know how they got from that one part to the other part

- anonymous

yeah well i cannot read what it says. good luck

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## More answers

- myininaya

http://www.cacr.math.uwaterloo.ca/hac/
its in chapter 11
on page 473 at the bottom

- myininaya

;p;

- myininaya

lol*

- myininaya

i wonder if james or zarkon could do it

- myininaya

oh its zarkon lol

- anonymous

good luck!

- KingGeorge

ask me next semester when I've taken cryptography, and I might be able to help you, but right now, I haven't got a clue.

- Zarkon

only the first two values of i will matter (i=0,1)
for i>1
you have a \((pq)^2\) part which is \(p^2qq=nq\) which is zero nod n

- myininaya

i don't see this (pq)^2 part

- myininaya

george what kind of math have you had?

- Zarkon

\[{k\choose i}x^{k-1}(ypq)^i\]
for \(i\ge2\)
\[{k\choose i}x^{k-1}(ypq)^i={k\choose i}x^{k-1}(y^i)(pq)^{i-2}p^2qq\]
\[=\left({k\choose i}x^{k-1}(y^i)(pq)^{i-2}q\right)\times n\]

- myininaya

ok i see

- myininaya

you are so smart to notice the first two values will only matter since n mod n is like totally 0
thanks zarkon

- KingGeorge

I've only had a year and a half of college level math so far, so that means, calc 1-3, lin. algebra, abstract algebra, and analysis

- Zarkon

no problem :)

- myininaya

is there any number theory in abstract algebra i can't remember

- KingGeorge

not very much. I'm taking intro to number theory, and cryptography next semester.

- myininaya

i like cryptography

- myininaya

number theory is so cool and interesting to me
although my skills suck right now

- KingGeorge

It certainly sounds fun. I'm definitely enjoying my abstract algebra class right now. We had the barest hints of some number theory in discrete math so I'm not completely helpless.

- myininaya

i like these math puzzles

- myininaya

differential equations is not as fun to me but i do like the remedial kind lol

- myininaya

zarkon do you think there is hope for my brain?

- KingGeorge

From my experience, I don't like differential equations very much. Granted, I've never had a full course in it, but it just isn't my thing.

- Zarkon

there is!

- myininaya

i feel like i'm trapped inside with an apes' brain

- Zarkon

A very smart ape ;)

- myininaya

thanks i take that as a compliment

- Zarkon

If you want a fun class...Take a course in measure theoretic probability theory.

- myininaya

he says that because he is a stat nerd

- KingGeorge

I don't think my school has that class...

- myininaya

my doesn't either

- Zarkon

or a class in stochastic processes

- Zarkon

sometimes it will fall under the title of applied probability

- myininaya

i think they might have that

- myininaya

i always had a 10 foot pole when it came to statistics
i only had to put it down when the course in stat was required

- KingGeorge

I'm personally more of an algebra person. Stats was interesting at first, but then it got boring.

- myininaya

There are some cool things though in stat i do admit

- Zarkon

There is plenty of really nice mathematics in statistics

- KingGeorge

It was the same with calculus for me. Interesting at first, and then it just stopped interesting me.

- Zarkon

A lot of multivariate calculus and matrix theory

- myininaya

zarkon can i ask another question

- myininaya

this is my last problem with this proof...

- Zarkon

ok

- myininaya

omg never i got it lol

- myininaya

i mean nvm

- myininaya

i was typing it all out then i realized oh yeah lol

- Zarkon

ok :)

- myininaya

ok i feel good about this proof thanks for all your help

- Zarkon

good...no problem

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