myininaya
  • myininaya
I have the following information: \[n=p^2q\] \[k \ge 4\] \[0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i can't even read this what class?
myininaya
  • myininaya
i made a mistake \[\sum_{i=0}^{k}\left(\begin{matrix} k \\ i \end{matrix}\right) x^{k-i}(ypq)^i \equiv x^k+kypqx^{k-1}\] I'm trying to follow a proof but i don't know how they got from that one part to the other part
anonymous
  • anonymous
yeah well i cannot read what it says. good luck

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myininaya
  • myininaya
http://www.cacr.math.uwaterloo.ca/hac/ its in chapter 11 on page 473 at the bottom
myininaya
  • myininaya
;p;
myininaya
  • myininaya
lol*
myininaya
  • myininaya
i wonder if james or zarkon could do it
myininaya
  • myininaya
oh its zarkon lol
anonymous
  • anonymous
good luck!
KingGeorge
  • KingGeorge
ask me next semester when I've taken cryptography, and I might be able to help you, but right now, I haven't got a clue.
Zarkon
  • Zarkon
only the first two values of i will matter (i=0,1) for i>1 you have a \((pq)^2\) part which is \(p^2qq=nq\) which is zero nod n
myininaya
  • myininaya
i don't see this (pq)^2 part
myininaya
  • myininaya
george what kind of math have you had?
Zarkon
  • Zarkon
\[{k\choose i}x^{k-1}(ypq)^i\] for \(i\ge2\) \[{k\choose i}x^{k-1}(ypq)^i={k\choose i}x^{k-1}(y^i)(pq)^{i-2}p^2qq\] \[=\left({k\choose i}x^{k-1}(y^i)(pq)^{i-2}q\right)\times n\]
myininaya
  • myininaya
ok i see
myininaya
  • myininaya
you are so smart to notice the first two values will only matter since n mod n is like totally 0 thanks zarkon
KingGeorge
  • KingGeorge
I've only had a year and a half of college level math so far, so that means, calc 1-3, lin. algebra, abstract algebra, and analysis
Zarkon
  • Zarkon
no problem :)
myininaya
  • myininaya
is there any number theory in abstract algebra i can't remember
KingGeorge
  • KingGeorge
not very much. I'm taking intro to number theory, and cryptography next semester.
myininaya
  • myininaya
i like cryptography
myininaya
  • myininaya
number theory is so cool and interesting to me although my skills suck right now
KingGeorge
  • KingGeorge
It certainly sounds fun. I'm definitely enjoying my abstract algebra class right now. We had the barest hints of some number theory in discrete math so I'm not completely helpless.
myininaya
  • myininaya
i like these math puzzles
myininaya
  • myininaya
differential equations is not as fun to me but i do like the remedial kind lol
myininaya
  • myininaya
zarkon do you think there is hope for my brain?
KingGeorge
  • KingGeorge
From my experience, I don't like differential equations very much. Granted, I've never had a full course in it, but it just isn't my thing.
Zarkon
  • Zarkon
there is!
myininaya
  • myininaya
i feel like i'm trapped inside with an apes' brain
Zarkon
  • Zarkon
A very smart ape ;)
myininaya
  • myininaya
thanks i take that as a compliment
Zarkon
  • Zarkon
If you want a fun class...Take a course in measure theoretic probability theory.
myininaya
  • myininaya
he says that because he is a stat nerd
KingGeorge
  • KingGeorge
I don't think my school has that class...
myininaya
  • myininaya
my doesn't either
Zarkon
  • Zarkon
or a class in stochastic processes
Zarkon
  • Zarkon
sometimes it will fall under the title of applied probability
myininaya
  • myininaya
i think they might have that
myininaya
  • myininaya
i always had a 10 foot pole when it came to statistics i only had to put it down when the course in stat was required
KingGeorge
  • KingGeorge
I'm personally more of an algebra person. Stats was interesting at first, but then it got boring.
myininaya
  • myininaya
There are some cool things though in stat i do admit
Zarkon
  • Zarkon
There is plenty of really nice mathematics in statistics
KingGeorge
  • KingGeorge
It was the same with calculus for me. Interesting at first, and then it just stopped interesting me.
Zarkon
  • Zarkon
A lot of multivariate calculus and matrix theory
myininaya
  • myininaya
zarkon can i ask another question
myininaya
  • myininaya
this is my last problem with this proof...
Zarkon
  • Zarkon
ok
myininaya
  • myininaya
omg never i got it lol
myininaya
  • myininaya
i mean nvm
myininaya
  • myininaya
i was typing it all out then i realized oh yeah lol
Zarkon
  • Zarkon
ok :)
myininaya
  • myininaya
ok i feel good about this proof thanks for all your help
Zarkon
  • Zarkon
good...no problem

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