Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

iMABOSS` Group Title

how are carbon atoms transferred between molecules

  • 3 years ago
  • 3 years ago

  • This Question is Closed
  1. blues Group Title
    Best Response
    You've already chosen the best response.
    Medals 3

    They're not, generally. A case could exist where a covalent bond forms between carbons of two different molecules, A and B, so that they become one molecule. If a different bond then broke in what had been Molecule B so that it dissociated, leaving part of the initial molecule bound to A, the net result would be the "transfer" of one or more carbon atoms from molecule B to molecule A. But in general, molecules don't "trade" or "transfer" whole atoms. Particularly in biologic systems, where energy barriers involved in bond making and breaking events are, in general, high.

    • 3 years ago
  2. iMABOSS` Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks !

    • 3 years ago
  3. TlJesusFreak37 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    What about in Photosynthesis and Cellular respiration?

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.