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i would write both sides in terms of sin(x) and cos(x) and clear the compound fractions

and then you might have to use some other identities

break up the LHS into \[\frac{sec x}{tan x - cot x} + \frac{-csc x}{tan x - cot x} \]

my advice would be to multiply by one using \[\frac{sinx}{sinx} \]

he means turn sec x into \[\frac{1}{cos x} \] etc...

hmmm

i tried turning tan into sin/cos and cot into cis/sin and then I got all tans and cos's too

|dw:1322797409581:dw|

Now. Use the same technique on the right side.

this doesn't look like an identity

oh my apologies

it is not

oh wait a minute if I change both sides then I can get them to be equal

try x=pi/3
both sides have different outputs

one side is approximately 1.366
the other side is .73205

the equation does hold for some values but not all which makes it not an identity

Thanks you guys =) i guess i need much more practice

start with|dw:1322798230411:dw|

So how did you get the denominator to be a product instead of a difference?

so you wouldn't have that product anymore

yeah

i still have like 18 questions to go...sigh...

trig identities :P not functions

Also, potter, are you absolutely sure that you copied the problem correctly?

Nope I understand...thank you everyone :) now i need to practice it

ok have fun

is potter okay?

yep potter's fine :)

harry potter? lol is that what you were thinking?

yeah xD

it wouldn't be so bad to be the most powerful wizard of all time

yeah :( then i woulnt have to worry about these math problems lol

you could just turn a math problem you didn't feel like working on into a bunny

LOL hahaha

too bad i cant give u another medal for that :P