Probability with Huntington's disease?
Huntington disease is a rare degenerative human disease determined by a dominant allele, HD. The disorder is usually manifested after the age of 45. A young man has learned that his father has developed the disease; his mother does not have the disease (and does not carry to HD disease allele).
What is the probability that the young man will later develop the disease?
I went for 50%?
If the young man has a child with a woman who does not carry the HD disease allele, what is the probability that their first child will be affected by Huntington disease as
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Check this out: http://uk.answers.yahoo.com/question/index?qid=20111201132717AARTsnN
Same question and there is an answer:
"You're correct that the man has a 50% probability of carrying the Huntington's allele.
Now, if he does have it, the probability that his first child will also inherit the Huntington's allele is also 50%. But there is only a 50% chance that the man has it to give to his son. So:
.5 X .5 = 0.25 = 25%
There is a 25% chance that the man's first child will be affected by Huntington's disease."