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moneybird Group Title

If frac{a}{b} = frac{c}{d}, then prove that frac{a+kc}{b+kd} = frac{a}{b} where k can be all real numbers.

  • 2 years ago
  • 2 years ago

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  1. moneybird Group Title
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    \[\frac{a}{b} = \frac{c}{d}\]

    • 2 years ago
  2. moneybird Group Title
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    show that \[\frac{a+kc}{b+kd} = \frac{a}{b} \]

    • 2 years ago
  3. Hero Group Title
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    I have it

    • 2 years ago
  4. Hero Group Title
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    It wasn't really that hard

    • 2 years ago
  5. Hero Group Title
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    b(a+kc) = a(b+kd) ab + bkc = ab + akd bkc = akd bc = ad c/d =a/b

    • 2 years ago
  6. Tomas.A Group Title
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    i made this myself too, wooo

    • 2 years ago
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