anonymous
  • anonymous
What is the sum of the arithmetic sequence 136, 124, 112 …, if there are 36 terms? –2,736 –2,664 –2,628 –2,700
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I believe it is -2664?
Mr.Math
  • Mr.Math
Are you sure?
Mr.Math
  • Mr.Math
What's the common difference between each successive members?

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Mr.Math
  • Mr.Math
Oh sorry, I read the choices as the members of the sequence. My bad!
ash2326
  • ash2326
a1=136 an=a1+(n-1)d an=136+(36-1)(-12) an=136-420 an=-284 an=-284 is the 36th term sum =n/2(a1+a36) =36/2(136-284) =18*(-148) -2664
Mr.Math
  • Mr.Math
-2664 is right.
anonymous
  • anonymous
Haha thank you :)
Mr.Math
  • Mr.Math
Haha you're welcome :P

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