A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
mitosuki
 3 years ago
What is the sum of the arithmetic sequence 136, 124, 112 …, if there are 36 terms?
–2,736
–2,664
–2,628
–2,700
mitosuki
 3 years ago
What is the sum of the arithmetic sequence 136, 124, 112 …, if there are 36 terms? –2,736 –2,664 –2,628 –2,700

This Question is Closed

mitosuki
 3 years ago
Best ResponseYou've already chosen the best response.0I believe it is 2664?

Mr.Math
 3 years ago
Best ResponseYou've already chosen the best response.2What's the common difference between each successive members?

Mr.Math
 3 years ago
Best ResponseYou've already chosen the best response.2Oh sorry, I read the choices as the members of the sequence. My bad!

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0a1=136 an=a1+(n1)d an=136+(361)(12) an=136420 an=284 an=284 is the 36th term sum =n/2(a1+a36) =36/2(136284) =18*(148) 2664
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.