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Sirlw
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In 1981, about $1.1 million was lost due to fires. In 1988, the loss was about $ 9 . 6 million.
What is the percent change and how?
 2 years ago
 2 years ago
Sirlw Group Title
In 1981, about $1.1 million was lost due to fires. In 1988, the loss was about $ 9 . 6 million. What is the percent change and how?
 2 years ago
 2 years ago

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Sirlw Group TitleBest ResponseYou've already chosen the best response.0
dw:1323131567020:dw
 2 years ago

Sirlw Group TitleBest ResponseYou've already chosen the best response.0
? did i do it right?
 2 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.1
its calculated like this \[{ 9.6 \over 1.1 } * 100\]
 2 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.1
872.7272727272727%
 2 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.1
dont forget to click good answer
 2 years ago

Sirlw Group TitleBest ResponseYou've already chosen the best response.0
i dont get it
 2 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.1
well when you try and find out how much the percentage has increased by you take the number its increased to divided by the number it was e.g. the number it increased to was 9.6 million and the number it was is 1.1 million and to get the answer in a percentage you multiply by 100 try it with any number you will see what i am talking about
 2 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.1
what dont you understand?
 2 years ago

Sirlw Group TitleBest ResponseYou've already chosen the best response.0
In the text book, " You find the difference between the two values. Next, put the original value in the bottom." You want to find the percent." Put a denominator of 100 (100%0 and a variable ( X ) as numerator
 2 years ago

Sirlw Group TitleBest ResponseYou've already chosen the best response.0
much like proportions
 2 years ago

Sirlw Group TitleBest ResponseYou've already chosen the best response.0
\[\left(\begin{matrix}8.5 \\1.1\end{matrix}\right)\] \[\left(\begin{matrix}X\\ 100 percent\end{matrix}\right)\]
 2 years ago
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