anonymous
  • anonymous
Use any method to simplify complex fraction.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\left(\begin{matrix}25z^2x^8 \\ 49\end{matrix}\right)/\left(\begin{matrix}175x^4z^7 \\ 21\end{matrix}\right)\]
anonymous
  • anonymous
that easy we been laerned how to do that
anonymous
  • anonymous
I'm not sure on how to do it can you help me out?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Mr.Math
  • Mr.Math
\[{25z^2x^8 \over 49} \div {175x^4z^7 \over 21}?\]
anonymous
  • anonymous
Yes that is the problem sorry should have put division sign
anonymous
  • anonymous
sure just do the like terms first like 175x -25x then subtract one from z then substract 49 from 21
Mr.Math
  • Mr.Math
\[={25z^2x^8 \over 49}\times {21 \over 175x^4z^7}={25z^2x^8 \over 175x^4z^7}\times{21 \over 49}={x^4 \over 7z^5}\times{3 \over 7}={3x^4 \over 49z^5}.\]
anonymous
  • anonymous
thanks man i really appreciate it.

Looking for something else?

Not the answer you are looking for? Search for more explanations.