Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.2
2y2=15 or 2y2=15 solve both for y
 3 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.0
i thought you cant have an abosolute value that = to a negative number?
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
we have something=positive
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
not something=negative
 3 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.0
but you wrote or 2y2=15 ?
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
\[2y=17 => y=\frac{17}{2}\] \[2y=13 => y=\frac{13}{2}\] i wrote that because we havesomething=positive gives us two cases
 3 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.0
oh ok but if it is something = negative then we have no soloution right?
 3 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.0
thanks for that was abit confused
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
tomas yes you can probably have several i know for a fact you can have two i don't think there is a limit
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
f(x)>=0 so thats why f(x) can not have negative output
 3 years ago

lilg132 Group TitleBest ResponseYou've already chosen the best response.0
ok thanks :)
 3 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.