Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

LoveYou*69

  • 4 years ago

simplify: x^2 - 16x + 64 over x^2 - 64

  • This Question is Closed
  1. wasiqss
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lolx easiest

  2. wasiqss
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    answer is (x-8) over (x+8)

  3. lalaly
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    \[\frac{x^2-16x+64}{x^2-64}= \frac{ \cancel{(x-8)}(x-8)}{\cancel{(x-8)}(x+8)}\]

  4. wasiqss
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wow lalaly ur work is soo organised :P

  5. LoveYou*69
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Thank you all! :D Sorry, I'm not too good at algebra...

  6. lalaly
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    =)

  7. wasiqss
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    honey u r gud at nthin :D

  8. LoveYou*69
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    haha i know no need for the reminder

  9. wasiqss
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hehe

  10. LoveYou*69
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    lol maybe i shouldn't have given you a medal hon :P

  11. wasiqss
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha u have given now so no choice back :D

  12. LoveYou*69
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    i know >.<

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy