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jpomer325
 3 years ago
Best ResponseYou've already chosen the best response.0can you rephrase the question?

Gabi148
 3 years ago
Best ResponseYou've already chosen the best response.0how to solve problem number 1

jpomer325
 3 years ago
Best ResponseYou've already chosen the best response.0alright this is gonna take a while to type so hold on one sec

jpomer325
 3 years ago
Best ResponseYou've already chosen the best response.0So here's the initial problem: \[(9(1)) \div (3/2) \div [(1)^{(11)\times(3)}+(1/2)]\] You need to do anything in parenthesis first so do (11)*(3) in the exponent first: \[(8) \div (3/2) \div [(1)^{33}+(1/2)]\] Now you need to do the exponents next so calculate (1)^33: \[(8) \div (3/2) \div [1+(1/2)]\] Now we go back to doing what's in parenthesis so do 1+(1/2): \[(8) \div (3/2) \div (1/2)\] Now we can divide, but dividing a fraction is the same as multiplying its inverse, so we get: \[(8) \times (2/3) \times (2)\] Then just multiply 8 * (2/3) and multiply that number by 2 and you get your answer: \[(16/3) \times (2) = (32/3)\] Final answer: (32/3)
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