## Gabi148 Group Title how to order of operation with fractions six steps 2 years ago 2 years ago

1. jpomer325 Group Title

can you rephrase the question?

2. Gabi148 Group Title

how to solve problem number 1

3. jpomer325 Group Title

alright this is gonna take a while to type so hold on one sec

4. jpomer325 Group Title

So here's the initial problem: $(-9-(-1)) \div (-3/2) \div [(-1)^{(-11)\times(-3)}+(1/2)]$ You need to do anything in parenthesis first so do (-11)*(-3) in the exponent first: $(-8) \div (-3/2) \div [(-1)^{33}+(1/2)]$ Now you need to do the exponents next so calculate (-1)^33: $(-8) \div (-3/2) \div [-1+(1/2)]$ Now we go back to doing what's in parenthesis so do -1+(1/2): $(-8) \div (-3/2) \div (-1/2)$ Now we can divide, but dividing a fraction is the same as multiplying its inverse, so we get: $(-8) \times (-2/3) \times (-2)$ Then just multiply -8 * (-2/3) and multiply that number by -2 and you get your answer: $(16/3) \times (-2) = (-32/3)$ Final answer: (-32/3)

5. jpomer325 Group Title

you got all that?

6. Gabi148 Group Title

yep

7. Gabi148 Group Title

thanks muchas gracias