Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

jpomer325Best ResponseYou've already chosen the best response.0
can you rephrase the question?
 2 years ago

Gabi148Best ResponseYou've already chosen the best response.0
how to solve problem number 1
 2 years ago

jpomer325Best ResponseYou've already chosen the best response.0
alright this is gonna take a while to type so hold on one sec
 2 years ago

jpomer325Best ResponseYou've already chosen the best response.0
So here's the initial problem: \[(9(1)) \div (3/2) \div [(1)^{(11)\times(3)}+(1/2)]\] You need to do anything in parenthesis first so do (11)*(3) in the exponent first: \[(8) \div (3/2) \div [(1)^{33}+(1/2)]\] Now you need to do the exponents next so calculate (1)^33: \[(8) \div (3/2) \div [1+(1/2)]\] Now we go back to doing what's in parenthesis so do 1+(1/2): \[(8) \div (3/2) \div (1/2)\] Now we can divide, but dividing a fraction is the same as multiplying its inverse, so we get: \[(8) \times (2/3) \times (2)\] Then just multiply 8 * (2/3) and multiply that number by 2 and you get your answer: \[(16/3) \times (2) = (32/3)\] Final answer: (32/3)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.