Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Gabi148

  • 4 years ago

how to order of operation with fractions six steps

  • This Question is Closed
  1. jpomer325
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you rephrase the question?

  2. Gabi148
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how to solve problem number 1

    1 Attachment
  3. jpomer325
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    alright this is gonna take a while to type so hold on one sec

  4. jpomer325
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So here's the initial problem: \[(-9-(-1)) \div (-3/2) \div [(-1)^{(-11)\times(-3)}+(1/2)]\] You need to do anything in parenthesis first so do (-11)*(-3) in the exponent first: \[(-8) \div (-3/2) \div [(-1)^{33}+(1/2)]\] Now you need to do the exponents next so calculate (-1)^33: \[(-8) \div (-3/2) \div [-1+(1/2)]\] Now we go back to doing what's in parenthesis so do -1+(1/2): \[(-8) \div (-3/2) \div (-1/2)\] Now we can divide, but dividing a fraction is the same as multiplying its inverse, so we get: \[(-8) \times (-2/3) \times (-2)\] Then just multiply -8 * (-2/3) and multiply that number by -2 and you get your answer: \[(16/3) \times (-2) = (-32/3)\] Final answer: (-32/3)

  5. jpomer325
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you got all that?

  6. Gabi148
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yep

  7. Gabi148
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks muchas gracias

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy