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Gabi148

how to order of operation with fractions six steps

  • 2 years ago
  • 2 years ago

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  1. jpomer325
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    can you rephrase the question?

    • 2 years ago
  2. Gabi148
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    how to solve problem number 1

    • 2 years ago
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  3. jpomer325
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    alright this is gonna take a while to type so hold on one sec

    • 2 years ago
  4. jpomer325
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    So here's the initial problem: \[(-9-(-1)) \div (-3/2) \div [(-1)^{(-11)\times(-3)}+(1/2)]\] You need to do anything in parenthesis first so do (-11)*(-3) in the exponent first: \[(-8) \div (-3/2) \div [(-1)^{33}+(1/2)]\] Now you need to do the exponents next so calculate (-1)^33: \[(-8) \div (-3/2) \div [-1+(1/2)]\] Now we go back to doing what's in parenthesis so do -1+(1/2): \[(-8) \div (-3/2) \div (-1/2)\] Now we can divide, but dividing a fraction is the same as multiplying its inverse, so we get: \[(-8) \times (-2/3) \times (-2)\] Then just multiply -8 * (-2/3) and multiply that number by -2 and you get your answer: \[(16/3) \times (-2) = (-32/3)\] Final answer: (-32/3)

    • 2 years ago
  5. jpomer325
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    you got all that?

    • 2 years ago
  6. Gabi148
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    yep

    • 2 years ago
  7. Gabi148
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    thanks muchas gracias

    • 2 years ago
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