anonymous
  • anonymous
how to order of operation with fractions six steps
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
can you rephrase the question?
anonymous
  • anonymous
how to solve problem number 1
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anonymous
  • anonymous
alright this is gonna take a while to type so hold on one sec

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anonymous
  • anonymous
So here's the initial problem: \[(-9-(-1)) \div (-3/2) \div [(-1)^{(-11)\times(-3)}+(1/2)]\] You need to do anything in parenthesis first so do (-11)*(-3) in the exponent first: \[(-8) \div (-3/2) \div [(-1)^{33}+(1/2)]\] Now you need to do the exponents next so calculate (-1)^33: \[(-8) \div (-3/2) \div [-1+(1/2)]\] Now we go back to doing what's in parenthesis so do -1+(1/2): \[(-8) \div (-3/2) \div (-1/2)\] Now we can divide, but dividing a fraction is the same as multiplying its inverse, so we get: \[(-8) \times (-2/3) \times (-2)\] Then just multiply -8 * (-2/3) and multiply that number by -2 and you get your answer: \[(16/3) \times (-2) = (-32/3)\] Final answer: (-32/3)
anonymous
  • anonymous
you got all that?
anonymous
  • anonymous
yep
anonymous
  • anonymous
thanks muchas gracias

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