anonymous
  • anonymous
solve the equation in the set of complex numbers. give only exact answers, not approximations... x^(-2)-x^(-1)=(3/4)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
how would you go about with the negative exponents?
anonymous
  • anonymous
x^(-n)=1/(x^n)
anonymous
  • anonymous
then how would you get rid of fractions?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[(2\pm 2\sqrt{2}i)/3\]
anonymous
  • anonymous
how'd you get that..?
anonymous
  • anonymous
solving the equation... :D
anonymous
  • anonymous
nice haha but im still confused on what to do after the x's are on the bottom part of the fractions
anonymous
  • anonymous
make the bottom part x^2 u will get like this: (1-x)/x^2=3/4 after cross multiplication, u can get a quadratic expression, solve that u will get the answer :)
anonymous
  • anonymous
ok so i got to the (1-x)/x^2=3/4 what do i do next? O.o
anonymous
  • anonymous
cross multiplication..
anonymous
  • anonymous
\[x^{-2}-x^{-1}=(3/4)\]\[\Leftrightarrow\frac{1}{x^2}-\frac{1}{x}=\frac{3}{4}\]
anonymous
  • anonymous
agree with dalvoron. Crossed multiply it and get x-x^2=3/4. then transpose 3/4 to the other side:)
anonymous
  • anonymous
am i supposed to get \[1\pm \sqrt{2}i/2\]?
anonymous
  • anonymous
No need for complex numbers here.\[\frac{1}{x^2}-\frac{1}{x}=\frac{3}{4}\]\[\Leftrightarrow \frac{4}{x^2}-\frac{4}{x}=3\]\[\Leftrightarrow 4-4x=3x^2\]
anonymous
  • anonymous
thanks! i just use the quadratic formula and then get both answers :D
anonymous
  • anonymous
Quite right, quite right. Regular factorising is possible also. What did you get as your solutions for x?
anonymous
  • anonymous
2/3,-2
anonymous
  • anonymous
Correct, good job!
anonymous
  • anonymous
THANKS :D
anonymous
  • anonymous
i have a few more problem that i cant get -.-

Looking for something else?

Not the answer you are looking for? Search for more explanations.