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 3 years ago
solve the equation in the set of complex numbers. give only exact answers, not approximations...
x^(2)x^(1)=(3/4)
 3 years ago
solve the equation in the set of complex numbers. give only exact answers, not approximations... x^(2)x^(1)=(3/4)

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MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0how would you go about with the negative exponents?

MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0then how would you get rid of fractions?

Arnab09
 3 years ago
Best ResponseYou've already chosen the best response.0\[(2\pm 2\sqrt{2}i)/3\]

MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0how'd you get that..?

Arnab09
 3 years ago
Best ResponseYou've already chosen the best response.0solving the equation... :D

MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0nice haha but im still confused on what to do after the x's are on the bottom part of the fractions

Arnab09
 3 years ago
Best ResponseYou've already chosen the best response.0make the bottom part x^2 u will get like this: (1x)/x^2=3/4 after cross multiplication, u can get a quadratic expression, solve that u will get the answer :)

MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0ok so i got to the (1x)/x^2=3/4 what do i do next? O.o

Dalvoron
 3 years ago
Best ResponseYou've already chosen the best response.1\[x^{2}x^{1}=(3/4)\]\[\Leftrightarrow\frac{1}{x^2}\frac{1}{x}=\frac{3}{4}\]

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0agree with dalvoron. Crossed multiply it and get xx^2=3/4. then transpose 3/4 to the other side:)

MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0am i supposed to get \[1\pm \sqrt{2}i/2\]?

Dalvoron
 3 years ago
Best ResponseYou've already chosen the best response.1No need for complex numbers here.\[\frac{1}{x^2}\frac{1}{x}=\frac{3}{4}\]\[\Leftrightarrow \frac{4}{x^2}\frac{4}{x}=3\]\[\Leftrightarrow 44x=3x^2\]

MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0thanks! i just use the quadratic formula and then get both answers :D

Dalvoron
 3 years ago
Best ResponseYou've already chosen the best response.1Quite right, quite right. Regular factorising is possible also. What did you get as your solutions for x?

MoreForJoe
 3 years ago
Best ResponseYou've already chosen the best response.0i have a few more problem that i cant get .
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