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solve the equation in the set of complex numbers. give only exact answers, not approximations...
x^(2)x^(1)=(3/4)
 2 years ago
 2 years ago
solve the equation in the set of complex numbers. give only exact answers, not approximations... x^(2)x^(1)=(3/4)
 2 years ago
 2 years ago

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MoreForJoeBest ResponseYou've already chosen the best response.0
how would you go about with the negative exponents?
 2 years ago

MoreForJoeBest ResponseYou've already chosen the best response.0
then how would you get rid of fractions?
 2 years ago

Arnab09Best ResponseYou've already chosen the best response.0
\[(2\pm 2\sqrt{2}i)/3\]
 2 years ago

MoreForJoeBest ResponseYou've already chosen the best response.0
how'd you get that..?
 2 years ago

Arnab09Best ResponseYou've already chosen the best response.0
solving the equation... :D
 2 years ago

MoreForJoeBest ResponseYou've already chosen the best response.0
nice haha but im still confused on what to do after the x's are on the bottom part of the fractions
 2 years ago

Arnab09Best ResponseYou've already chosen the best response.0
make the bottom part x^2 u will get like this: (1x)/x^2=3/4 after cross multiplication, u can get a quadratic expression, solve that u will get the answer :)
 2 years ago

MoreForJoeBest ResponseYou've already chosen the best response.0
ok so i got to the (1x)/x^2=3/4 what do i do next? O.o
 2 years ago

DalvoronBest ResponseYou've already chosen the best response.1
\[x^{2}x^{1}=(3/4)\]\[\Leftrightarrow\frac{1}{x^2}\frac{1}{x}=\frac{3}{4}\]
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
agree with dalvoron. Crossed multiply it and get xx^2=3/4. then transpose 3/4 to the other side:)
 2 years ago

MoreForJoeBest ResponseYou've already chosen the best response.0
am i supposed to get \[1\pm \sqrt{2}i/2\]?
 2 years ago

DalvoronBest ResponseYou've already chosen the best response.1
No need for complex numbers here.\[\frac{1}{x^2}\frac{1}{x}=\frac{3}{4}\]\[\Leftrightarrow \frac{4}{x^2}\frac{4}{x}=3\]\[\Leftrightarrow 44x=3x^2\]
 2 years ago

MoreForJoeBest ResponseYou've already chosen the best response.0
thanks! i just use the quadratic formula and then get both answers :D
 2 years ago

DalvoronBest ResponseYou've already chosen the best response.1
Quite right, quite right. Regular factorising is possible also. What did you get as your solutions for x?
 2 years ago

MoreForJoeBest ResponseYou've already chosen the best response.0
i have a few more problem that i cant get .
 2 years ago
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