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how would you go about with the negative exponents?

x^(-n)=1/(x^n)

then how would you get rid of fractions?

\[(2\pm 2\sqrt{2}i)/3\]

how'd you get that..?

solving the equation... :D

nice haha but im still confused on what to do after the x's are on the bottom part of the fractions

ok so i got to the (1-x)/x^2=3/4 what do i do next? O.o

cross multiplication..

\[x^{-2}-x^{-1}=(3/4)\]\[\Leftrightarrow\frac{1}{x^2}-\frac{1}{x}=\frac{3}{4}\]

agree with dalvoron. Crossed multiply it and get x-x^2=3/4. then transpose 3/4 to the other side:)

am i supposed to get \[1\pm \sqrt{2}i/2\]?

thanks! i just use the quadratic formula and then get both answers :D

2/3,-2

Correct, good job!

THANKS :D

i have a few more problem that i cant get -.-