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Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
x(y+1) + y = 13 so x = (13 y)/(y+1)
 3 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
substitute that in for x, and the rest is just a simple 2 equations with 2 unknown variable problem
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
please wait.....lemme try...
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
what is 13y*z+1?
 3 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
can you be more clear? post your work
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
wait i got (13z13yzy)/y+1 +z=5
 3 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
ok use equation 2 now: y(z+1) + z = 9 so y = (9z)/(z+1) plug that in for y
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
i got z^2+2z=3
 3 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
ok. that is a quadratic equation. solve it
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
can z hav 2 values?
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
then ans is 1,3
 3 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
now substitute for z in the other equations
 3 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
(for simplicity's sake, substitute into the original equations)
 3 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
there you go. That's it!
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
thnx....ure awesome!!!!!!!!!!!!!
 3 years ago
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