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King

  • 4 years ago

xy+x+y=-13 yz+y+z=-9 xz+x+z=5 Find x,y,z.

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  1. Lumenaire
    • 4 years ago
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    x(y+1) + y = -13 so x = (-13 -y)/(y+1)

  2. Lumenaire
    • 4 years ago
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    substitute that in for x, and the rest is just a simple 2 equations with 2 unknown variable problem

  3. King
    • 4 years ago
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    please wait.....lemme try...

  4. Lumenaire
    • 4 years ago
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    try.

  5. King
    • 4 years ago
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    what is -13-y*z+1?

  6. Lumenaire
    • 4 years ago
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    can you be more clear? post your work

  7. King
    • 4 years ago
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    wait i got (-13z-13-yz-y)/y+1 +z=5

  8. Lumenaire
    • 4 years ago
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    ok use equation 2 now: y(z+1) + z = -9 so y = (-9-z)/(z+1) plug that in for y

  9. King
    • 4 years ago
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    i got z^2+2z=3

  10. Lumenaire
    • 4 years ago
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    ok. that is a quadratic equation. solve it

  11. King
    • 4 years ago
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    can z hav 2 values?

  12. Lumenaire
    • 4 years ago
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    yes

  13. King
    • 4 years ago
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    then ans is 1,-3

  14. King
    • 4 years ago
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    for z

  15. Lumenaire
    • 4 years ago
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    correct

  16. Lumenaire
    • 4 years ago
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    now substitute for z in the other equations

  17. Lumenaire
    • 4 years ago
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    (for simplicity's sake, substitute into the original equations)

  18. King
    • 4 years ago
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    ok ,y =-5,3

  19. Lumenaire
    • 4 years ago
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    correct

  20. King
    • 4 years ago
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    x=-4,2

  21. Lumenaire
    • 4 years ago
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    there you go. That's it!

  22. King
    • 4 years ago
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    thnx....ure awesome!!!!!!!!!!!!!

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