King
xy+x+y=13
yz+y+z=9
xz+x+z=5
Find x,y,z.



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Lumenaire
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1
x(y+1) + y = 13
so x = (13 y)/(y+1)

Lumenaire
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1
substitute that in for x, and the rest is just a simple 2 equations with 2 unknown variable problem

King
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please wait.....lemme try...

Lumenaire
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try.

King
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what is 13y*z+1?

Lumenaire
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can you be more clear? post your work

King
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wait i got (13z13yzy)/y+1 +z=5

Lumenaire
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1
ok use equation 2 now:
y(z+1) + z = 9
so y = (9z)/(z+1)
plug that in for y

King
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i got z^2+2z=3

Lumenaire
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1
ok. that is a quadratic equation. solve it

King
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can z hav 2 values?

Lumenaire
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yes

King
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then ans is 1,3

King
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for z

Lumenaire
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correct

Lumenaire
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now substitute for z in the other equations

Lumenaire
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1
(for simplicity's sake, substitute into the original equations)

King
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ok ,y =5,3

Lumenaire
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correct

King
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x=4,2

Lumenaire
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there you go. That's it!

King
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thnx....ure awesome!!!!!!!!!!!!!