xy+x+y=-13 yz+y+z=-9 xz+x+z=5 Find x,y,z.

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xy+x+y=-13 yz+y+z=-9 xz+x+z=5 Find x,y,z.

Mathematics
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x(y+1) + y = -13 so x = (-13 -y)/(y+1)
substitute that in for x, and the rest is just a simple 2 equations with 2 unknown variable problem
please wait.....lemme try...

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what is -13-y*z+1?
can you be more clear? post your work
wait i got (-13z-13-yz-y)/y+1 +z=5
ok use equation 2 now: y(z+1) + z = -9 so y = (-9-z)/(z+1) plug that in for y
i got z^2+2z=3
ok. that is a quadratic equation. solve it
can z hav 2 values?
yes
then ans is 1,-3
for z
correct
now substitute for z in the other equations
(for simplicity's sake, substitute into the original equations)
ok ,y =-5,3
correct
x=-4,2
there you go. That's it!
thnx....ure awesome!!!!!!!!!!!!!

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