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King Group Title

xy+x+y=-13 yz+y+z=-9 xz+x+z=5 Find x,y,z.

  • 2 years ago
  • 2 years ago

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  1. Lumenaire Group Title
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    x(y+1) + y = -13 so x = (-13 -y)/(y+1)

    • 2 years ago
  2. Lumenaire Group Title
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    substitute that in for x, and the rest is just a simple 2 equations with 2 unknown variable problem

    • 2 years ago
  3. King Group Title
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    please wait.....lemme try...

    • 2 years ago
  4. Lumenaire Group Title
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    try.

    • 2 years ago
  5. King Group Title
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    what is -13-y*z+1?

    • 2 years ago
  6. Lumenaire Group Title
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    can you be more clear? post your work

    • 2 years ago
  7. King Group Title
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    wait i got (-13z-13-yz-y)/y+1 +z=5

    • 2 years ago
  8. Lumenaire Group Title
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    ok use equation 2 now: y(z+1) + z = -9 so y = (-9-z)/(z+1) plug that in for y

    • 2 years ago
  9. King Group Title
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    i got z^2+2z=3

    • 2 years ago
  10. Lumenaire Group Title
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    ok. that is a quadratic equation. solve it

    • 2 years ago
  11. King Group Title
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    can z hav 2 values?

    • 2 years ago
  12. Lumenaire Group Title
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    yes

    • 2 years ago
  13. King Group Title
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    then ans is 1,-3

    • 2 years ago
  14. King Group Title
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    for z

    • 2 years ago
  15. Lumenaire Group Title
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    correct

    • 2 years ago
  16. Lumenaire Group Title
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    now substitute for z in the other equations

    • 2 years ago
  17. Lumenaire Group Title
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    (for simplicity's sake, substitute into the original equations)

    • 2 years ago
  18. King Group Title
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    ok ,y =-5,3

    • 2 years ago
  19. Lumenaire Group Title
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    correct

    • 2 years ago
  20. King Group Title
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    x=-4,2

    • 2 years ago
  21. Lumenaire Group Title
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    there you go. That's it!

    • 2 years ago
  22. King Group Title
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    thnx....ure awesome!!!!!!!!!!!!!

    • 2 years ago
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