meow18

Find the distance between J and K.
A. 13.42
B. 8.49
C. 7.21
D. 12.65

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meow18

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Sbdenney

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B

Tomas.A

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B

Sbdenney

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Pythagorean Therom

Sbdenney

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A squared + B squared = C squared

hoblos

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\[sqrt{\7\2\}\ \=\ \8\.\4\]

Sbdenney

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Ur pretty BTW

meow18

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Thankss (:

Rajesh2184

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Given: point k is (-1,3) and J is (5,9)
using Distance formula = sqrt [(9-3)^2 +(5-(-1)^2]
= sqrt[(6^2 +6^2]
= sqrt(36+36)
=sqrt(72)
=8.4852813 = 8.49
So the answer is option B