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abz_tech
 3 years ago
20 grams of ice at 0(degree) celcius was added to 80 grams of water which is in a copper calorimeter of mass 50 grams. the temperature of the calorimeter and water was 25 (degree) celcius. when the ice was melted the temperature of the calorimeter and water was 5.1(degree) celcius. Assuming that no heat is transferred to or from the surroundings, calculate the specific latent heat of fusion of ice.
specific heat capacity of water = 4180 J kg1 K1
specific heat capacity of copper= 390 J kg1 K1
abz_tech
 3 years ago
20 grams of ice at 0(degree) celcius was added to 80 grams of water which is in a copper calorimeter of mass 50 grams. the temperature of the calorimeter and water was 25 (degree) celcius. when the ice was melted the temperature of the calorimeter and water was 5.1(degree) celcius. Assuming that no heat is transferred to or from the surroundings, calculate the specific latent heat of fusion of ice. specific heat capacity of water = 4180 J kg1 K1 specific heat capacity of copper= 390 J kg1 K1

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Barlando
 3 years ago
Best ResponseYou've already chosen the best response.0I'm just taking a guess here set your mc∆t of water plus mc∆t of copper equal to the mc∆t of the ice
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