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abz_tech
20 grams of ice at 0(degree) celcius was added to 80 grams of water which is in a copper calorimeter of mass 50 grams. the temperature of the calorimeter and water was 25 (degree) celcius. when the ice was melted the temperature of the calorimeter and water was 5.1(degree) celcius. Assuming that no heat is transferred to or from the surroundings, calculate the specific latent heat of fusion of ice. specific heat capacity of water = 4180 J kg-1 K-1 specific heat capacity of copper= 390 J kg-1 K-1
I'm just taking a guess here set your mc∆t of water plus mc∆t of copper equal to the mc∆t of the ice