anonymous
  • anonymous
20 grams of ice at 0(degree) celcius was added to 80 grams of water which is in a copper calorimeter of mass 50 grams. the temperature of the calorimeter and water was 25 (degree) celcius. when the ice was melted the temperature of the calorimeter and water was 5.1(degree) celcius. Assuming that no heat is transferred to or from the surroundings, calculate the specific latent heat of fusion of ice. specific heat capacity of water = 4180 J kg-1 K-1 specific heat capacity of copper= 390 J kg-1 K-1
Physics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
I'm just taking a guess here set your mc∆t of water plus mc∆t of copper equal to the mc∆t of the ice

Looking for something else?

Not the answer you are looking for? Search for more explanations.